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mestny [16]
2 years ago
14

The center circle on a playing field has a radius of 7.5m find its circumference

Mathematics
1 answer:
Nady [450]2 years ago
3 0
<h3>Given:</h3>
  • r= 7.5 m
<h3>Note that:</h3>
  • r= radius
<h3>To find:</h3>

The circumference of the circular playing field.

<h3>Solution:</h3>

\huge\boxed{Formula:C= 2\pi{r}}

We'll have to multiply 2, π and radius.

Substitute the values according to the formula.

C= 2× \pi ×7.5

C= 47.12389

\large\boxed{C= 47.12 \: m}

<u>Therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>circumference</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>circular</u><u> </u><u>playing</u><u> </u><u>field</u><u> </u><u>is</u><u> </u><u>47.12</u><u> </u><u>feets</u><u>.</u>

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The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.
MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle =3\times\ side

3\times\ side =[tex]81\sqrt{3}

Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm

Thus from the diagram , Side AB=BC=AC= 27\sqrt{3} \ cm

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus \angle OBC = 30°

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2}  } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\

Thus ,apothem  OE= 13.5 cm

Now for radius,

We consider ΔOBE

cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB}  \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0
3 years ago
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