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Lady bird [3.3K]
3 years ago
14

Given the system of equations, what is the solution? x + 3y = 5 x - 3y = -1

Mathematics
2 answers:
Elza [17]3 years ago
8 0
\left \{ {{x + 3y = 5} \atop {x - 3y = -1}} \right.

Immediately, you can tell that 3y and -3y will cancel out using elimination.  That would be the easiest solving method to use here.  Set up the problems like this, add them, and solve for the remaining variable:

<span>x + 3y = 5
x - 3y = -1
</span>---------------
2x      = 4
x = 2

Now that you know what x is, you can substitute this value for x in one of the equations:

x + 3y = 5

2 + 3y = 5

3y = 3

y = 1

The solution to this system would be (2, 1).

You can perform a check for each equation to verify that this is the correct solution:

2 + 3(1) = 5

2 + 3 = 5

5 = 5
<em>Correct</em>

2 - 3(1) = -1

2 - 3 = -1

-1 = -1
<em>Correct</em>
mr_godi [17]3 years ago
3 0
\begin{cases}x+3y=5\\x-3y=-1 \end{cases}\\---------(+)\\\\x+x+3y-3y=5+(-1)\\\\2x=4\qquad|:2\\\\\boxed{x=2}\\\\\\\\x+3y=5\\\\2+3y=5\qquad|-2\\\\2+3y-2=5-2\\\\3y=3\qquad|:3\\\\\boxed{y=1}

The solution is (2; 1)
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The 't' test statistic t =  \frac{x-μ}{\frac{sig}{\sqrt{n} } }

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3 years ago
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