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lidiya [134]
3 years ago
8

A new car worth $20,000 loses 20% of its value every year. Is the value of the car represented by a linear or exponential functi

on?
A) linear
B) exponential
C) both linear and exponential
D) neither linear or exponential
Mathematics
2 answers:
BARSIC [14]3 years ago
7 0
The answer would be:

B) Exponential
Kryger [21]3 years ago
3 0
B) Exponential. Because it keeps losing 20% of what the previous years amount was so it decreases by a smaller factor each year

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tatiyna

Answer:

b_{1}=\frac{2A}{h}-b_{2}

Step-by-step explanation:

Given: A=\frac{1}{2}(b_{1} +b_{2})h

We need to completely isolate b_{1} to solve.

A=\frac{1}{2}(b_{1} +b_{2})h

A=(\frac{1}{2}b_{1} +\frac{1}{2} b_{2})h

A=\frac{1}{2}b_{1} h+\frac{1}{2}b_{2}h

-\frac{1}{2}b_{1}h+A=\frac{1}{2}b_{2}h

-\frac{1}{2}b_{1}h=-A+\frac{1}{2}b_{2}h

-\frac{1}{2}b_{1}=\frac{-A}{h}+\frac{1}{2}b_{2}

Finally, multiply both sides by -2 to completely isolate b_{1}.

b_{1}=\frac{2A}{h}-b_{2}

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