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aivan3 [116]
3 years ago
7

Which expression represents the distance between the points (11, 4) and (5,8)?

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
4 0

Answer:

\displaystyle d = 2\sqrt{13}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (11, 4) → x₁ = 11, y₁ = 4

Point (5, 8) → x₂ = 5, y₂ = 8

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formula]:                                                       \displaystyle d = \sqrt{(5-11)^2+(8-4)^2}
  2. [√Radical] (Parenthesis) Subtract:                                                                 \displaystyle d = \sqrt{(-6)^2+(4)^2}
  3. [√Radical] Evaluate exponents:                                                                    \displaystyle d = \sqrt{36+16}
  4. [√Radical] Add:                                                                                               \displaystyle d = \sqrt{52}
  5. [√Radical] Simplify:                                                                                         \displaystyle d = 2\sqrt{13}
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Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

f(t) =18,500(1.03)^t  

1st blank:

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1.03

3

18,500

2nd blank:

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3rd blank:

19,055

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My answer:

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1st blank:

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f(0) =18,500(1)\\ f(0) =18,500

So we choose D for 1st blank

2nd and 3rd blank:

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=> 2nd blank: 1

=> 3rd blank: 1.03

Hope it will find you well.

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