Lol
trouble varies directly as distance
lets say t=trouble and d=distance
t=kd
k is constant
given
when t=20, and d=400
find k
20=400k
divide by 400 both sides
1/20=k
t=(1/20)d
given, d=60
find t
t=(1/20)60
t=60/20
t=3
3 troubles
p(the person does not use any facility)= 59/130
Reasonable because the three items altogether cost about $40
3,200,00 converted to scientific notation is 3.2 x 106
