3 years ago

The circle below is centered at the point (-1, 2) and has a radius of length 3.

Mathematics

1 answer:

expeople1 [14]3 years ago

6 0

Answer:

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r the radius

Here (h, k) = (- 1, 2) and r = 3, thus

(x - (- 1))² + (y - 2)² = 3², that is

(x + 1)² + (y - 2)² = 9

You might be interested in

Help please asap!!!!!!!!!

goldenfox [79]

Try C but im not 100% sure though

3 0

4 years ago

Find the zeroes of the following equation:

weqwewe [10]

Answer: $\bold{x=\dfrac{1\pm \sqrt5}{2}}$

both zeros are irrational numbers

Step-by-step explanation:

Note: The question would have made more sense if if it was 2/x = x - 1 but I will answer it as written.

$\dfrac{1}{x}=x-1\qquad \text{Restriction: }x\neq 0\\\\\\\text{Cross multiply, simplify, and set equal to zero:}\\1=x(x-1)\\\\1=x^2-x\\\\0=x^2-x-1\\\\\\\text{This is not factorable so you will need to use Quadratic Formula:}\\\\x=\dfrac{-(-1)\pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}\\\\\\x=\dfrac{1\pm \sqrt5}{2}$