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3 years ago

If she will buy 35 T-shirts, 45 pairs of shorts, and 25 windbreakers, what will be her total cost?

Mathematics

1 answer:

svetoff [14.1K]3 years ago

4 0

Answer:

$Total\ Cost = \$973.75$

Step-by-step explanation:

Given (Missing part of question)

T-shirts = $7.50

Shorts = $9.00

Windbreakers = $12.25

Required

Determine the total cost

Total Cost is calculated as follows;

$Total\ Cost = Costs\ of\ T-Shirts + Costs\ of\ Shorts + Costs\ of\ Windbreakers$

$Total\ Cost = 35 * \$7.5 + 45 * \$9.00 + 25 * \$12.25$

$Total\ Cost = \$262.5 + \$405.00 + \$306.25$

$Total\ Cost = \$973.75$

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The sign of the product of –35 and –625 is

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Step-by-step explanation:

The mathematical sign for the operation is subtraction.

To Solve This You Will Need To;

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3 years ago

Read 2 more answers

The proportion of brown M&M's in a milk chocolate packet is approximately 14%. Suppose a package of M&M's typically cont

marshall27 [118]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the scenario above :

A) State the random variable.

The random variable is the p opoertion of brown M&M's in a milk chocolate packet.

B.) Argue that this is a binomial experiment.

Each trial is independent for a total number of 52 trials with a set probability of success at 0.14

C) probability that 6 M&M's are brown:.

P(x) = nCx * p^x * (1-p)^(n-x)

p = 0.14 ; (1 - p) = 0.86 ; n = 52 ; x = 6

P(x = 6) = 52C6 × 0.14^6 × 0.86^46

= 20358520 × 0.00000752954 × 0.00097035078

= 0.1487

D) P(x =25)

P(x = 25) = 52C25 × 0.14^25 × 0.86^27

= 477551179875952 × 449.987958058*10^(-24) × 0.01703955245

= 0.00000000366

E) P(x = 52)

P(x = 52) = 52C52 × 0.14^52 × 0.86^0

= 1 × 3968.78758299*10^(-48) × 1

= 3968.78758299*10^(-48)

F) yes it would be unusual, because such probability is extremely low. However, if a huge or substantial number of trials such may occur

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3 years ago

The area of a rhombus is 90 square inches. If the longer diagonal measures 18 inches, what is the length of the shorter diagonal

lorasvet [3.4K]

10 Inches

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