We have been given that Morgan is throwing a pizza party. She has 1 7/8 pounds of cheese available and she needs 1/5 pound of cheese to make each pizza. We are asked to find the number of full pizzas that Morgan can make with the amount of cheese she has.
To solve our given problem, we will divide total amount of cheese by amount of cheese used to make each pizza.
Now we will convert our division problem into multiplication problem by flipping the 2nd fraction.
We are asked to find the number of full pizzas and we can see that Morgan can make 9 full and 
pizzas.
Since there are 9 full pizzas, therefore, Morgan can make 9 full pizzas with the amount of cheese she has.
Answer:
Step-by-step explanation:
<u>Increase by 23%</u>
- x + 23% of x =
- x + (23/100)x =
- x + 0.23x =
- (1 + 0.23)x =
- 1.23x
1.23 is the answer
Answer:
12.543
Step-by-step explanation:
Answer:
it is the third option of g(x)=|x-1|+3x-1
the way I look at this is by visualizing the translations using the parent function of f(x)=|x|
the function moved up three and to the right by one which led to my conclusion
Answer:
45°, 45°, 90°
Step-by-step explanation:
Find the vectors to represent each sides
AB =<3-1, 6-0>=<2,6>
AC = < -1-1, 4 - 0 > = < -2, 4>
Magnitude of the vectors
AB = √(2²+6²) = 6.32
AC = √ ((-2)² + 4²) = 4.47
cosθ = vector of AB × vector AC / ( Product of the magnitude of AB and AC) = 2 × (-2) + (6×4)/ (6.32×4.47) = 20 / 28.2504
θ = arcos(20 / 28.2504 ) approx = 45°
Magnitude of the vectors
BA =<1-3,0-6>=<-2,-6>
BC =<-1-3,4-6>=<-4,-2>
Magnitude of the vectors equals
BA = √((-2)² + (-6)²) = 6.325
BC = √((-4)² + (-2)²) = 4.4721
cosθ = (-2×-4) + (-6 ×-2) / (6.325 × 4.4721) = 20 / 28.286
θ = arcos (20 / 28.286 ) = 45°
Magnitude of the vectors
CB =<3--1, 6-4>=<4,2>
CA=<1--1,0-4>=<2,-4>
Magnitude of the vector =
CB = √(4² + 2²) = 4.4721
CA = √(2² + (-4)²) = 4.4721
cosθ = (4×2) + (2×-4) / (4.4721×4.4721) = 0
θ = arcos 0 = 90°
