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Virty [35]
3 years ago
9

9. Solve the equation. (1 point) 4x = 68 64 72 12 17

Mathematics
1 answer:
Oksana_A [137]3 years ago
5 0

Answer:

17

Step-by-step explanation:

<em>or</em><em>,</em><em> </em><em> </em>4x= 68

<em>or</em><em>,</em><em> </em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>6</em><em>8</em><em>/</em><em> </em><em>4</em>

<em> </em><em> </em><em> </em><em>:</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>1</em><em>7</em>

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A recent health report revealed that a woman with insurance spends an average of 2.3 days in the hospital following a routine ch
cupoosta [38]

Answer:

t=\frac{2.3-1.9}{\sqrt{\frac{0.6^2}{16}+\frac{0.3^2}{16}}}}=2.385  

p_v =2*P(t_{30}>2.385)=0.0236

Comparing the p value with the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis

The confidence interval would be given by:

(2.3 -1.9) - 2.75*\sqrt{\frac{0.6^2}{16}+\frac{0.3^2}{16}}}=-0.0611

(2.3 -1.9) + 2.75* \sqrt{\frac{0.6^2}{16}+\frac{0.3^2}{16}}}=0.861

Step-by-step explanation:

Data given and notation

\bar X_{insurance}=2.3 represent the mean for insurance

\bar X_{No. ins}=1.9 represent the mean withour insurance

s_{Insurance}=0.6 represent the sample standard deviation for the insurance case

s_{No. Ins}=0.3 represent the sample standard deviation for the No insurance case

n_{Insurance}=16 sample size for insurance

n_{No. Iss}=16 sample size for no insurance

t would represent the statistic (variable of interest)

\alpha=0.01 significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different, the system of hypothesis would be:

Null hypothesis:\mu_{Insu}=\mu_{No. Ins}

Alternative hypothesis:\mu_{Ins} \neq \mu_{No. Ins}

Since we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

t=\frac{\bar X_{Ins}-\bar X_{No.Ins}}{\sqrt{\frac{s^2_{Ins}}{n_{Ins}}+\frac{s^2_{No. Ins}}{n_{No. Ins}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

t=\frac{2.3-1.9}{\sqrt{\frac{0.6^2}{16}+\frac{0.3^2}{16}}}}=2.385  

What is the p-value for this hypothesis test?

The degrees of freedom are given by:

df = n_{ins} +n_{No Ins}-2=16+16-2 =30

Since is a bilateral test the p value would be:

p_v =2*P(t_{30}>2.385)=0.0236

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis

The confidence interval would be given by:

(2.3 -1.9) - 2.75*\sqrt{\frac{0.6^2}{16}+\frac{0.3^2}{16}}}=-0.0611

(2.3 -1.9) + 2.75* \sqrt{\frac{0.6^2}{16}+\frac{0.3^2}{16}}}=0.861

6 0
2 years ago
Let​ R(x), C(x), and​ P(x) be,​ respectively, the​ revenue, cost, and​ profit, in​ dollars, from the production and sale of x it
sp2606 [1]

Answer:

P(x) = -0.004x^2 - 3.7x - 50

Step-by-step explanation:

We have to find profit P(x).

This can be easily found using a formula for Profit given the Revenue and Cost.

Profit = Revenue - Cost

P(x) = R(x) - C(x)

Given that:

R(x) = 6x

C(x) = 0.004x^2 + 2.3x + 50

to find P(x) we can simply subtract R(x) by C(x).

P(x) = R(x) - C(x)

P(x) = (6x) - (0.004x^2 + 2.3x + 50)

P(x) = 6x - 0.004x^2 - 2.3x - 50

and finally, after simplify this equation subtracting 6x by 2.3x.

this is the equation for the profit P(x)

P(x) = -0.004x^2 - 3.7x - 50

3 0
3 years ago
The length of a rectangle is twice its width. if the perimeter of the rectangle is 36 cm , find its area.
Brut [27]
L = Length
W = Width

L x W = area
Length = 2w

Lets find the width by solving for w.
2w + w = 36 
3w = 36
3w/3 = 36 / 3 
w = 12

So
L = 2 x 12 = 24
W = 12
L X W = area
24 x 12 = 288 cm^2

6 0
3 years ago
What would you expect the nominal rate of interest to be if the real rate is 4.4 percent and the expected inflation rate is 7.5
ANTONII [103]

Answer:

Nominal Interest rate=11.9%

Step-by-step explanations:

The Fisher effect is a theory propounded by an economist named Irving Fisher.

Fisher's equation shows the relationship between real Interest rate, expected inflation rate and nominal Interest rate.

It can be calculated by subtracting the expected inflation rate from the nominal Interest rate to give the real Interest rate.

Real Interest rate= nominal Interest rate - expected inflation rate

Given,

Real Interest rate= 4.4%=0.044

Expected inflation rate=7.5%=0.075

Nominal Interest rate=?

Therefore,

Real Interest rate=nominal Interest rate - expected inflation rate

Nominal Interest rate=Real Interest rate+expected inflation rate

Nominal Interest rate=0.044+0.075

Nominal Interest rate=0.119

Nominal Interest rate=11.9%

5 0
3 years ago
Please help meeeee. I literally learned this last year but my dum mb self forgot hot to do it
Aleks [24]

It would be 30 because 10^4 is 10000 and 10000 times 12 is 120000 and 10^3 is 1000 and 1000 times 4 is 4000 so 120000 divided by 4000 is 30

8 0
3 years ago
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