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3 years ago

9

A widescreen television sells for $1050. The sales tax is 8%.

1 answer:

hodyreva [135]3 years ago

3 0

A is the answer,,,,,,,,,,

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3 pounds to 18 ounces

Allisa [31]

Answer:

divide the pounds to get 18 ounces

Step-by-step explanation:

i think?

4 0

2 years ago

I need help finishing the proof

erastova [34]

Answer:

See proof

Step-by-step explanation:

Statements Reasons

1. $\overline{AEC}$ bisects $\angle DAB,\ \angle 1\cong \angle 2$ Given

2. $\angle 3\cong \angle 4$ Definition of angle bisector

3. $\overline{AE}\cong \overline{AE}$ Reflexive property of equality

4. $\triangle ABE \cong \triangle ADE$ AAS postulate

5. $\overline {AB}\cong \overline{AD}$ Congruent triangles have congruent corresponding sides

6. $\overline{AC}\cong \overline{AC}$ Reflexive property of equality

7. $\triangle BAC \cong \triangle DAC$ SAS postulate

8. $\overline {BC}\cong \overline{CD}$ Congruent triangles have congruent corresponding sides

6 0

3 years ago

If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

3 years ago

Somebody explain pls!!!!!

Furkat [3]

Step-by-step explanation:

Using log properties

$log_{7}(rz {}^{12} )$

$log_{7}(r) + log_{7}(z {}^{12} )$

Then

$log_{7}(r) + 12 log_{7}(z)$

Plug in the knowns

$- 7.87 + 12( - 12.59)$

$- 158.95$

5 0

1 year ago

The image represents what geometric construction?

boyakko [2]

<span>C)
Parallel lines construction

because they are parallel to each other</span>

8 0

3 years ago

Read 2 more answers