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natita [175]
3 years ago
11

Round 4.35 to the nearest tenths

Mathematics
2 answers:
bonufazy [111]3 years ago
5 0
It will be 4.4 when rounded up.
JulijaS [17]3 years ago
3 0
4.35 rounded to the nearest tenths would be 4.4.
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Answer:

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Step-by-step explanation:

A = bh

270 = 15b

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the weights of ten cats in pounds are 14, 10, 11, 9, 12, 8, 8, 10, 7, and 10. what is the mean absolute deviation of the weights
BabaBlast [244]

Answer:

HOW TO DO STEP BY STEP:)

Original set ={14, 10, 11, 9, 12, 8, 8, 10, 7,10}

n = 8 is the number of values in that set above

Add up the values 12+11+7+10+10+11+6+8+14+8 = 97

Divide that sum by n = 8 to get 97/8 = 12. So the mean = 12

For each value in the original set {14, 10, 11, 9, 12, 8, 8, 10, 7,10} subtract off the mean = 12. Apply the absolute value to ensure the result is positive or zero

|x - mean| = |14 - 12| = -2

|x - mean| = |10 - 12| = 2

|x - mean| = |11- 12| = 1

|x - mean| = |9 - 12| = 3

|x - mean| = |12 - 12| =0

|x - mean| = |8 - 12| = 4

|x - mean| = |8 - 12| = 4

|x - mean| = |10 - 12| =2

|x - mean| = |7 - 12| = 5

|x - mean| = |10 - 12| = 2

The set of results we get are: {-2,2,1,3,4,4,2,5,2 } -2,2,1,3,4,4,2,5,= 21, then we divide 21 that over n = 12 (21/12) to get  = 1.75

Therefore the mean absolute deviation (MAD) is 1.75

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