(x + 1)²(x - 4)(-2x + 3)
(x + 1)(x + 1)(x - 4)(-2x + 3)
(x² + x + x + 1)(-8x² + 3x + 8x - 12)
(x² + 2x + 1)(-8x² + 11x - 12)
(-8x^4 + 11x³ - 12x² - 16x³ + 11x² - 12x - 8x² + 11x - 12)
(8x^4 + 11x³ - 16x³ - 12x² + 11x² - 8x² - 12x - 11x - 12)
8x^4 - 5x³ + 15x² - 23x - 12
Answer:
The 20th percentile of coffee temperature is 155.4532 degrees Fahrenheit.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 160 degrees
Standard Deviation, σ = 5.4 degrees
We are given that the distribution of temperature of coffee is a bell shaped distribution that is a normal distribution.
Formula:
We have to find the value of x such that the probability is 0.2
Calculation the value from standard normal z table, we have,
Thus,

The 20th percentile of coffee temperature is 155.4532 degrees Fahrenheit.
Answer:
-1
—— = -0.25000
4
Step-by-step explanation: