There were 2 solutions that i came up with. Here is the first one. I rearranged the eqaution by subtracting what is to the right of thr equal sign. Multiply the coefficeint of the first term by the constant 5 x (-1)= -5. Then you would find 2 factors of -5 whose sum equals the coefficient of the middle term which is 20. -5+1= -4 and -1+5=4. the eqaution then comes to 5t^2-20t-1=0. you would solve 5t^2-20t-1=0. you would divide both sides of the equal sign by 5. t^-4t-1/5=0. then t^2-4t=1/5. add 4 to both sides of the equation. so we get 21/5+ 4 + 4t -t^2=21/5. it then comes out to be t^2-4t+t=t-2^2. according to the law of transitivity it is t-2^2=21/5.
t =(20+√420)/10=2+1/5√<span> 105 </span><span>= 4.049 </span>.
Answer:
19
Step-by-step explanation:
38/2 =19
Answer: Is In The Explanation
Step-by-step explanation: For the answer to the question above,
A) You just fill in 0 for w in the problem and anything raised to the power of 0 is 1, so 230(1) is 230, and that is the old factory and at 0 for the new, it is at 190. Subtract then explain why you did what you did.
B) I believe what they are asking for you to do, is you can take each week from the new factory and subtract it and find the equation for the new factory, you already know the growth rate for the old factory= 230(1.1)^w.
C) You take your old factory's equation and plug in numbers until one of them is greater at the new factory.
1. The information given in the problem is:
- <span>The length of a rectangular garden is 8 feet longer than the width.
- </span><span>The garden is surrounded by a 4-foot sidewalk.
- The area of the sidewalk is 320 ft</span>².
2. So, the length of the rectangular garden is:
L1=8+W1
3. The formula for calculate the area of the sidewalk, is:
A2=L2xW2
"A2" is the area of the sidewalk (A2=320 ft²).
"L2" is the length of the sidewalk.
"W2" is the widht of the sidewalk.
4. The length of the sidewalk (L2) is:
L2=L1+4+4 (4 feet on each side)
L2=L1+8
5. When you substitute L1=8+W1 into the equation L2=L1+8, you obtain:
L2=8+W1+8
L2=W1+16
6. The widht of the sidewalk is:
W2=W1+4+4
W2=W1+8
7. Now, you must substitute the length and the widht of the sidewalk into the formula A2=L2xW2:
A2=L2xW2
A2=(W1+16)(W1+8)
320=W1²+16W1+8W1+128
W1²+16W1+8W1+128-320=0
W1²+16W1+8W1-192=0
8. When you solve the quadratic equation, you obtain the value of W1:
W1=16.97 ft
9. Finally, you must substitute the value of W1 into the formula L1=8+W1:
L1=8+W1
L1=8+16.97
L1=24.97 ft
10. Therefore, the dimensions of the garden are:
L1=24.97 ft
W1=16.97 ft
