Give three points for the equation 9x + 5y = 2 using an XY table and choosing your own values for x, and plot the line.
1 answer:
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Answer:
22) RT ; angles 2 and 4 are alternate interior angles
23) RT ; angles 1 and 3 are alternate interior angles
24) TV; same-side interior angles (some classes called them consecutive interior angles)
25) RV; same-side interior angles (some classes call them consecutive interior angles)
Step-by-step explanation:
The transversal is the a "line" going through at least 2 others helping to form the angles in question.
22) The line segment going through two line segments that contain angles 2 and 4 is:
RT.
Angles 2 and 4 are alternate interior angles because they happen inside the parallel lines on opposite sides of the transversal at the different intersections of RT and the parallel lines it goes through.
23) The line segment going through at least two line segments that contain angles 1 and 3 is:
RT.
Angles 1 and 3 are alternate interior angles because they happen inside the parallel lines on opposite sides of the transversal at the different intersections of RT and the parallel lines it goes through.
The cool thing about 24 and 25 is that they give you the transversal in the name of the angle.
24) Angles TVR and VTS are being formed by the line segment TV and the parallel line segments that it intersects. TV is the transversal.
Angles TVR and VTS are same side interior angles because they happen inside the parallel lines on the same side of the transerval at the different intersections of TV and the parallel lines it goes through.
25) Angles SRV and RVT are being formed by the line segment RV and the parallel line segments that it intersects. RV is the transversal.
Angles SRV and RVT are same side interior angles because they happen inside the parallel lines on the same side of the transerval at the different intersections of RV and the parallel lines it goes through.
Answer:
500 pounds
Step-by-step explanation:
Let the pressure applied to the leverage bar be represented by p
Let the distance from the object be represented by d.
The pressure applied to a leverage bar varies inversely as the distance from the object.
Written mathematically, we have:
Introducing the constant of proportionality
If 150 pounds is required for a distance of 10 inches from the object
- p=150 pounds
- d=10 inches
Therefore, the relationship between p and d is:
When d=3 Inches
The pressure applied when the distance is 3 inches is 500 pounds.