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Allisa [31]
3 years ago
15

How many solutions does the equation 3(x-5)-7=-3x8 have

Mathematics
1 answer:
LenaWriter [7]3 years ago
8 0

Answer:

not really good at maths. 15.33

Step-by-step explanation:

3(x-5)-7=3×8

3x-15-7=24

3x =24+15+7

3x = 46

Three will divide it's self to give you one and divide 46 to give you 15.333

(correct me if i'm wrong)

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20 points and a branliest if correct, ASAP please
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Nikolay [14]

Answer:

  linear

Step-by-step explanation:

The x-values all differ by 1, which is to say they are equally-spaced. The corresponding y-values all differ by -3. When (first) differences of equally-spaced values of y are constant, the function is of first degree, which is to say it is linear.

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If second differences are non-zero and constant, the function is of second degree, quadratic.

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Answer:

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Step-by-step explanation:

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Cans some one help this stinks so bad.
Darya [45]

Answer:

5,652,000

Step-by-step explanation:

1. Simplify 1/3 * 3.14

you'll end up with 3.14/3

2. Divide 3.14 by 3

this will give you 1.046

3. Raise 150 to the power of 2.

you now have 22,500

your equation is now: 1.046 * 22,500 * 240

4. Multiply 1.046 by 22,500

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4 0
4 years ago
NO LINKS!!! Please help me with this problem​
gogolik [260]

Answer:

  • length: 8
  • end points: (-8, 1), (0, 1)

Step-by-step explanation:

In the quadratic form ...

  (x -h)² = 4p(y -k)

The value 4p is the length of the latus rectum. It also tells the distance between the vertex (h, k) and the focus (h, k+p).

<h3>Application</h3>

The value of 4p is given as 8. This means p = 8/4 = 2.

The length of the latus rectum is 8.

The end points of the latus rectum have the same y-value as the focus:

  y = k +p = -1 +2 = 1

The end points of the latus rectum have x-values that are h±2p.

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The end points of the latus rectum are (-8, 1) and (0, 1).

7 0
2 years ago
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