<span>, y+2 = (x^2/2) - 2sin(y)
so we are taking the derivative y in respect to x so we have
dy/dx use chain rule on y
so y' = 2x/2 - 2cos(y)*y'
</span><span>Now rearrange it to solve for y'
y' = 2x/2 - 2cos(y)*y'
0 = x - 2cos(y)y' - y'
- x = 2cos(y)y' - y'
-x = y'(2cos(y) - 1)
-x/(2cos(y) - 1) = y'
</span><span>we know when f(2) = 0 so thus y = 0
so when
f'(2) = -2/(2cos(0)-1)
</span><span>2/2 = 1
</span><span>f'(2) = -2/(2cos(0)-1)
cos(0) = 1
thus
f'(2) = -2/(2(1)-1)
= -2/-1
= 2
f'(2) = 2
</span>
3x+1=2x+4+x
3x
3x+1=3x+4
-1 -1
3x=3x+3
-3x
x=3
i think that would be your anser
Answer:
f^-1(x) = ( x + 6 )/4
Step-by-step explanation:
f(x) is the same as...y = 4x + 6....and then try to make x the subject of formula
y + 6 = 4x
x = (y + 6)/4....then when writing f^-1(x)...replace y with x
f^-1(x) = ( x + 6 )/4
Answer:
d) 
Step-by-step explanation:
requires 
requires 
requires 
So, total amount of gasoline required for the trip is 
.
Answer:
a
Step-by-step explanation:
