Answer:
9 gallons of water per minute
Step-by-step explanation:
First identify what you know:
1) The pipe was flowing water for eight minutes.
2) In that eight minutes, 72 gallons of water came out.
So, if 72 gallons of water came out in eight minutes, how many gallons flowed out in a single minute? Well, assuming that the flow rate was consistent, then simply divide the total number of gallons that flowed out, by the number of minutes the pipe was open!
72/8 = 9
The pipe released 9 gallons of water per minute, thus resulting in 72 gallons of water in 8 minutes!
Hope this helps! :)
Step-by-step explanation:
the answer is 10x - 8.
3x+2
5x-7
2x-3
--------
10x-8
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-------- hope this helps you and please try to mark me as BRAINLIST.
Answer:
m∠FEH = 44°
m∠EHG = 64°
Step-by-step explanation:
1) The given information are;
The angle of arc m∠FEH = 272°, the measured angle of ∠EFG = 116°
Given that m∠FEH = 272°, therefore, arc ∠HGF = 360 - 272 = 88°
Therefore, angle subtended by arc ∠HGF at the center = 88°
The angle subtended by arc ∠HGF at the circumference = m∠FEH
∴ m∠FEH = 88°/2 = 44° (Angle subtended at the center = 2×angle subtended at the circumference)
m∠FEH = 44°
2) Similarly, m∠HGF is subtended by arc m FEH, therefore, m∠HGF = (arc m FEH)/2 = 272°/2 = 136°
The sum of angles in a quadrilateral = 360°
Therefore;
m∠FEH + m∠HGF + m∠EFG + m∠EHG = 360° (The sum of angles in a quadrilateral EFGH)
m∠EHG = 360° - (m∠FEH + m∠HGF + m∠EFG) = 360 - (44 + 136 + 116) = 64°
m∠EHG = 64°.
1 yd is equivalent to 3 ft, so 7 times 3 is 21. 21 is greater than 20, so your answer is 7 yd.
