M<1 = M<3
these 2 angles are equal for parallel lines
6x=120
X=120/6=20
Answer:
%82.5
Step-by-step explanation:
- The final exam of a particular class makes up 40% of the final grade
- Moe is failing the class with an average (arithmetic mean) of 45% just before taking the final exam.
From point 1 we know that Moe´s grade just before taking the final exam represents 60% of the final grade. Then, using the information in the point 2 we can compute Moe´s final grade as follows:
,
where FG is Moe´s Final Grade and FE is Moe´s final exam grade. Then,
.
So, in order to receive the passing grade average of 60% for the class Moe needs to obtain in his exam:
That is, he need al least %82.5 to obtain a passing grade.
There are several conditions where triangles can be proved similar:
AA - where two of the angles are same.
SAS - where two sides of a triangle compare to the corresponding sides in the other are in same proportion, and the angle in the middle are equal.
SSS - Where all sides in a triangle and the corresponding sides are in the same proportion.
In the case above, we can only use the method of SAS, as only two sides of the triangles are given.
<HMG = <JMK (vertically opposite angles)
HM/MK = 8/12 = 2/3
GM/MJ = 6/9 = 2/3
As the two sides of a triangle comparing to the corresponding sides in the other are in same proportion, and the angle in the middle are equal, the above triangles are similar, with the prove of SAS.
Therefore, the answer is C.yes by SAS.
Hope it helps!
12/20=.6
Thus, move the decimal point two places to the right, and the answer is 60%
Answer:
The triangles are congruent by congruency theorem SAS.
Step-by-step explanation:
Side-Angle-Side, as it suggests, is when a triangle is congruent by the order of congruent side, congruent angle, and another congruent side. If named certain ways, they can be congruent. Since the question does not provide a specific way of naming the triangles, we can assume that any way is allowed. 2.5 and 2.5 are congruent, followed by angles D and G which have the congruent angle markers. The congruent angles are followed by 1.7 and 1.7, making the triangles congruent by Side-Angle-Side.
