(x - 5i√2)(x +5i√2)
given the roots of a polynomial p(x), say x = a and x = b
then the factors are (x - a)(x - b)
and p(x) is the product of the factors ⇒ p(x) = (x - a)(x - b)
here x² + 50 = 0 ⇒ x² = - 50 → ( set = 0 for roots)
take the square root of both sides
x = ± √-50 = ± √(25 × 2 × -1) = √25 × √2 × √-1 = ± 5i√2
The roots are x = ± 5i√2
thus the factors are ( x - ( - 5i√2)) and (x - (+5i√2))
x² + 50 = (x + 5i√2)(x - 5i√2)
Answer:
Step-by-step explanation:
The slope is given to you by the line y = 1/4 x
The slope is just read as the number in front of x providing that the coefficient of y is 1. If that is not so, then you must divide by the coefficient in front of y. So far what you have is y = 1/4 x + b.
The second part of the question is to use the given point to find b.
x = 4
y = -1
b = ? substitute x and y to find b
y = 1/4 * 4 + b
- 1 = 1/4 * 4 + b
-1 = 1 + b
-2 = b
The equation of the line is y = 1/4 x - 2 Just to confirm this, I'm going to include the graph with the point 4,-1 on it.
I think the answer is C.
First start by factoring, you should get (2n-3)(n-2)=0
Then start to solve for n.
2n-3=0
n-2=0
n=2, n= 3/2
I hope that helps.