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3 years ago

Please help explanation if possible

Mathematics

1 answer:

spayn [35]3 years ago

8 0

Answer: 2 goes in the box

The solid boundary line equation is y = 2. The shaded region consists of this line and everything below it, which is describing $y \le 2$ . So y can be 2 or it can be smaller than 2.

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A study is conducted to determine whether a new cancer drug increases the mean survival time by at least 30 days for a certain t

anygoal [31]

Answer:

H0: The new cancer drug increases the mean survival time by 30 days

Ha: The new cancer drug increases the mean survival time by 30 or more than 30 days.

If fail to reject H0 (the null hypothesis), the conclusion is that the new cancer drug increases the mean survival time by 30 days.

Step-by-step explanation:

The null hypothesis is a statement from a population parameter which is either rejected or accepted (fail to reject) upon testing. It is expressed using the equality sign.

The alternate hypothesis is also a statement from a population parameter which negates the null hypothesis and is accepted if the null hypothesis is rejected. It is expressed using any of the inequality signs.

The test is a two-tailed test because the alternate hypothesis is expressed using more than or equal to.

If I fail to reject H0, it means the test statistic falls within the region bounded by the critical values.

It would therefore be concluded that the new cancer drug increases the mean survival time by 30 days.

8 0

3 years ago

Find the value of 7! 2!

gregori [183]

Answer: 350% is your answer just 7/2×100= 350%

Step-by-step explanation:

6 0

3 years ago

The length of a rectangle is five times its width.

Vera_Pavlovna [14]

Answer:

Step-by-step explanation:

l = 5w

A = l*w

180 = 5w *w

180 = 5w^2

Divide each side by 5

180/5 = 5w^2 /5

36 = w^2

Taking the square root of each side

sqrt(36) = sqrt(w)^2

6 =w

l = 5w = 5*6 = 30

The perimeter is

P = 2(l+w)

P = 2(6+30) = 2(36) = 72

4 0

3 years ago

A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.

noname [10]

Answer:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

Step-by-step explanation:

Given

$Volume = 128ft^3$

$L = 2W$

$Base\ Cost = \$9/ft^2$

$Sides\ Cost = \$6/ft^2$

Required

The dimension that minimizes the cost

The volume is:

$Volume = LWH$

This gives:

$128 = LWH$

Substitute $L = 2W$

$128 = 2W * WH$

$128 = 2W^2H$

Make H the subject

$H = \frac{128}{2W^2}$

$H = \frac{64}{W^2}$

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

$A = LW + 2(WH + LH)$

The cost is:

$Cost = 9 * LW + 6 * 2(WH + LH)$

$Cost = 9 * LW + 12(WH + LH)$

$Cost = 9 * LW + 12H(W + L)$

Substitute: $H = \frac{64}{W^2}$ and $L = 2W$

$Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)$

$Cost =18W^2 + \frac{768}{W^2}*3W$

$Cost =18W^2 + \frac{2304}{W}$

To minimize the cost, we differentiate

$C' =2*18W + -1 * 2304W^{-2}$

Then set to 0

$2*18W + -1 * 2304W^{-2} =0$

$36W - 2304W^{-2} =0$

Rewrite as:

$36W = 2304W^{-2}$

Divide both sides by W

$36 = 2304W^{-3}$

Rewrite as:

$36 = \frac{2304}{W^3}$

Solve for $W^3$

$W^3 = \frac{2304}{36}$

$W^3 = 64$

Take cube roots

$W = 4$

Recall that:

$L = 2W$

$L = 2 * 4$

$L = 8$

$H = \frac{64}{W^2}$

$H = \frac{64}{4^2}$

$H = \frac{64}{16}$

$H = 4$

Hence, the dimension that minimizes the cost is:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

8 0

2 years ago

Pls help me

deff fn [24]

Answer:

Angle 1: Can be measures of triangle: 84

Cannot be angle measures of triangle: 49, 47

Angle 2: Can be measures of triangle: none

Cannot be angle measures of triangle: 50,89,50

Angle 3: Can be angle measures of triangle: 75, 15, 45

Cannot be angle measures of triangle: none

Angle 4: Can be angle measures of triangle: none

Cannot be angle measures of triangle: 25, 22, 133

5 0

2 years ago