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3 years ago

I need help. I will give brainliest and 99 points

Mathematics

2 answers:

sammy [17]3 years ago

8 0

The triangles are similar because they both have the same same angles.
Why? Because the two triangles are both right triangles and they both have another angle that is the same (as indicated by the circle fragment on the picture). That means that the last angle will be the same. Triangles are similar when they have the same angles but don't have to have the same lengths.

If the triangles are similar, the side lengths are in ratios. You are given the length of the side that corresponds with the third angle, which are 4 and 15. So the ratio of the lengths of the small to large triangle is 4:15. You are given another length (Height of Annie's eyes), which is 5. This can help you find the height of the house.

Let x=height of the house.
So 4/15 = 5/x
4x=5*15=75
x=75/4
x=18.75 ft

Hope this helps!

Dominik [7]3 years ago

3 0

Hello!

The height of the house is 18.75 feet.

I hope it helps!

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6х + 17 = -7 justify each step

Tju [1.3M]

Answer:

x = -4

Step-by-step explanation:

Subtract 17 on both sides to get 6x = -24 then divide 6 to both sides to get your answer of x = -4

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3 years ago

Read 2 more answers

Let X = the time between two successive arrivals at the drive-up window of a local bank. If X has an exponential distribution wi

Illusion [34]

Answer:

(a) $E(X) = 1$

(b) $\sigma_X =1$

(d) P(2 ≤ X ≤ 5) = 0.1286

Step-by-step explanation:

From the given information; Let consider X to be the time between two successive arrivals at the drive-up window of a local bank.

However; If X is regarded as the exponential distribution with λ = 1 which is identical to a standard gamma distribution with ∝ = 1

The objective is to compute the following :

(a) The expected time between two successive arrivals is;

$E(X) = \dfrac{1}{\lambda}$

$E(X) = \dfrac{1}{1}$

$E(X) = 1$

(b) The standard deviation of the time between successive arrivals is;

$\sigma_X = \sqrt{\dfrac{1}{\lambda^2}}$

$\sigma_X ={\dfrac{1}{\lambda}}$

$\sigma_X ={\dfrac{1}{1}}$

$\sigma_X =1$

P(X ≤ 1) = 1 - e⁻¹

P(X ≤ 1) = 0.6321

(d) P(2 ≤ X ≤ 5)

P(2 ≤ X ≤ 5) = [1 - e⁻⁵] - [1 - e⁻²]

P(2 ≤ X ≤ 5) = 0.9933 - 0.8647

P(2 ≤ X ≤ 5) = 0.1286

7 0

3 years ago

An 80 kg boat that is 9.6 m in length is initially 7.6 m from the pier. A 46 kg child stands at the end of the boat closest to t

kakasveta [241]

Answer:

13.695 m

Step-by-step explanation:

The assumption made here is that the boat/water interface is essentially frictionless, so that the center of mass of the system remains in the same place as the occupant of the boat moves around.

We can find the sum of the moments of boat and child about the pier end:

(46 kg)(7.6 m) + (80 kg)((7.6 +9.6/2) m) = 1341.6 kg·m

After the child moves, the center of mass of boat and child is presumed to remain in the same place. If x is the new distance from the pier to the child, the sum of moments is now ...

46x +80(x-4.8)* = 1341.6

126x -384 = 1341.6

x = (1341.6 +384)/126 = 13 73/105 ≈ 13.695 . . . meters

The child is about 13.695 meters from the pier when she reaches the far end of the boat.

_____

* The center of mass of the boat alone is half its length closer to the pier than is the child, so is located at x-4.8 meters.

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3 years ago

Please someone help me !! :(

geniusboy [140]

Answer: 27 times bigger.

Step-by-step explanation:

You need to use the following formula to find the volume of a Square pyramid:

$V=\frac{1}{3}s^2h$

Where "s" is the edge of a side of the square base and "h" is the height of the pyramid.

Knowing that:

$s_A=12\ in\\\\h_A=8\ in\\\\\\s_B=36\ in\\\\h_B=24\ in$

You can find the volume of the Pyramid A and the volume of the Pyramid B:

$V_A=\frac{1}{3}(12\ in)^2(8\ in)\\\\V_A=384\ in^3\\\\\\V_B=\frac{1}{3}(36\ in)^2(24\ in)\\\\V_B=10,368\ in^3$

Finally divide the volume of the Pyramid B and the volume of the Pyramid A, in order to find how many times bigger than the Pyramid A is the Pyramid B.

You get:

$\frac{10,368\ in^3}{384\ in^3}=27$

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4 years ago

Jed took 2 free throws in 5 seconds Alex took four free throws in 12 seconds. did the two shoot free throws at the same rate?

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Jed: 2 free throws/ 5 sec= 0.4 free throw/sec.

Alex: 4 free throws/12 sec= 0.33333... free throw/sec.

The two did not shoot free throws at the same rate~

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3 years ago