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nikitadnepr [17]
3 years ago
11

An 80 kg boat that is 9.6 m in length is initially 7.6 m from the pier. A 46 kg child stands at the end of the boat closest to t

he pier. The child then notices a turtle on a rock at the far end of the boat and proceeds to walk to the far end of the boat to observe the turtle. How far is the child from the pier when she reaches the far end of the boat?
Mathematics
1 answer:
kakasveta [241]3 years ago
6 0

Answer:

  13.695 m

Step-by-step explanation:

The assumption made here is that the boat/water interface is essentially frictionless, so that the center of mass of the system remains in the same place as the occupant of the boat moves around.

__

We can find the sum of the moments of boat and child about the pier end:

  (46 kg)(7.6 m) + (80 kg)((7.6 +9.6/2) m) = 1341.6 kg·m

After the child moves, the center of mass of boat and child is presumed to remain in the same place. If x is the new distance from the pier to the child, the sum of moments is now ...

  46x +80(x-4.8)* = 1341.6

  126x -384 = 1341.6

  x = (1341.6 +384)/126 = 13 73/105 ≈ 13.695 . . . meters

The child is about 13.695 meters from the pier when she reaches the far end of the boat.

_____

* The center of mass of the boat alone is half its length closer to the pier than is the child, so is located at x-4.8 meters.

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(Score for Question 2: ___ of 10 points)
Vedmedyk [2.9K]

The area of room is 812 square feet, cost of carpet to cover the room is $6739.6 and the remaining square feet of carpet are covered by furniture is 203 square feet.

<h3>What is the area of trapezoid?</h3>

The area of the trapezoid is the space occupied by it on the two dimensional plane. The area of this figure is half of the product of height and sum of sides.

A=\dfrac{(a+b)h}{2}

Here, (a and b) are the base sides of the trapezoid and (h) is the height.

A room is shaped like a trapezoid which has the height of 28 feet and the length of sides as 23 ft and 35 ft. Thus, the area of it is,

A=\dfrac{(a+b)h}{2}\\A=\dfrac{(23+35)28}{2}\\A=812\rm\; ft^2

Carpet costs $8.30 per square foot. Thus, the cost of carpet with area 812 ft² is,

C=812×$8.30

C=$6739.6

Furniture covers 25% of the floor. Thus, the remaining square feet of carpet are covered by furniture is,

A=\dfrac{25}{100}\times812\\A=203\rm\; ft^2

Thus, the area of room is 812 square feet, cost of carpet to cover the room is $6739.6 and the remaining square feet of carpet are covered by furniture is 203 square feet.

Learn more about the area of trapezoid here;

brainly.com/question/1410008

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4 0
2 years ago
Which measurement is equivalent to 110 mL
ale4655 [162]
Your answer is 0.110 L

110mL=0.110L
4 0
3 years ago
Hi I need to know the slope(m) before 11:00 I know the y-intercept(b) is -3
Alexxandr [17]

Answer:

slope is 2/3

Step-by-step explanation:

y=mx + b where m is the slope

6 0
2 years ago
Due to a manufacturing error, two cans of regular soda were accidentally filled with diet soda and placed into a 18-pack. Suppos
crimeas [40]

Answer:

a) There is a 1.21% probability that both contain diet soda.

b) There is a 79.21% probability that both contain diet soda.

c)  P(X = 2) is unusual, P(X = 0) is not unusual

d) There is a 19.58% probability that exactly one is diet and exactly one is regular.

Step-by-step explanation:

There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

A number of sucesses x is considered unusually low if P(X \leq x) \leq 0.05 and unusually high if P(X \geq x) \geq 0.05

In this problem, we have that:

Two cans are randomly chosen, so n = 2

Two out of 18 cans are filled with diet coke, so \pi = \frac{2}{18} = 0.11

a) Determine the probability that both contain diet soda. P(both diet soda)

That is P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{2,2}(0.11)^{2}(0.89)^{0} = 0.0121

There is a 1.21% probability that both contain diet soda.

b)Determine the probability that both contain regular soda. P(both regular)

That is P(X = 0).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{2,0}(0.11)^{0}(0.89)^{2} = 0.7921

There is a 79.21% probability that both contain diet soda.

c) Would this be unusual?

We have that P(X = 2) is unusual, since P(X \geq 2) = P(X = 2) = 0.0121 \leq 0.05

For P(X = 0), it is not unusually high nor unusually low.

d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)

That is P(X = 1).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 1) = C_{2,1}(0.11)^{1}(0.89)^{1} = 0.1958

There is a 19.58% probability that exactly one is diet and exactly one is regular.

8 0
3 years ago
Simplify (-8)(-2) + 11<br> 027<br> 0 -1<br> 0-5
Schach [20]
Answer:-5
-8x-2=-16
-16+11=-5
4 0
3 years ago
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