I think 55 because you would multiply 11×5
Answer:

Step-by-step explanation:
we know that
To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.
we will proceed to verify each case to determine the solution of the problem
<u>case A)</u> 
Find the inverse of f(x)
Let
y=f(x)
Exchange variables x for y and y for x
Isolate the variable y


Let


therefore
f(x) and g(x) are inverse functions
<u>case B)</u> 
Find the inverse of f(x)
Let
y=f(x)
Exchange variables x for y and y for x
Isolate the variable y


Let


therefore
f(x) and g(x) are inverse functions
<u>case C)</u> ![f(x)=x^{5}, g(x)=\sqrt[5]{x}](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B5%7D%2C%20g%28x%29%3D%5Csqrt%5B5%5D%7Bx%7D)
Find the inverse of f(x)
Let
y=f(x)
Exchange variables x for y and y for x
Isolate the variable y
fifth root both members
![y=\sqrt[5]{x}](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B5%5D%7Bx%7D)
Let

![f^{-1}(x)=\sqrt[5]{x}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Csqrt%5B5%5D%7Bx%7D)
therefore
f(x) and g(x) are inverse functions
<u>case D)</u> 
Find the inverse of f(x)
Let
y=f(x)
Exchange variables x for y and y for x
Isolate the variable y





Let



therefore
f(x) and g(x) is not a pair of inverse functions
Answer:
x ≤ 3
Step-by-step explanation:
2(4+2x) ≥ 5x+5 (by PEDMAS, expand parentheses first)
4(2) + 2x(2) ≥ 5x + 5
8 + 4x ≥ 5x + 5 (subtract 8 from each side)
4x ≥ 5x + 5 - 8
4x ≥ 5x - 3 (subtract 5x from both sides)
4x -5x ≥ - 3
-x ≥ - 3 (multiply both sides by -1, remember to flip the inequality when multiplying both sides by a negative number)
x ≤ 3
Answer:
The answer is A
Step-by-step explanation:
Given that the equation of line is y = mx + c and the slope is 7 :
y = 7x + c
By substituting the coordinate(8,6) into the equation, in order to find the value of c:
6 = 7(8) + c
6 = 56 + c
c = 6 - 56
= -50
y = 7x - 50
(Hope this can help)
Answer:
25
Step-by-step explanation:
If HI and IJ are both the same and meet at the same point, the triangles would be the same.