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Vaselesa [24]
4 years ago
14

The perimeter of a square is equal to the circumference of a circle with a radius of 10 cm.

Mathematics
1 answer:
marta [7]4 years ago
3 0

Answer:

C = 2*3.14*10 = 62.8 cm = P of square

Area=1/16 * p2

=

246.49 cm2

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I need help pls I’ll mark you brain
Ket [755]

Answer:

I'm pretty sure it's B

Step-by-step explanation:

Stacy gets 2 cards each week, so you would multiply 2 cards by every week she volunteers. She started out with three cards, so therefore you would add 3.

5 0
3 years ago
Read 2 more answers
Jethro used dimensional analysis to convert one rate of speed to another. Two of the conversion factors he used are 5280 ft/1 mi
NNADVOKAT [17]

The units of the initial and final rates of speed are;

<u><em>Initial rate of Speed = ft/hr</em></u>

<u><em>Final rate of speed = mi/min</em></u>

  • We are told that the conversion factors he used are;

5280 ft/1 mi and 1 hr/60 min

  • Now, the meaning of 5280 ft/1 mi denotes that;

5280 ft mile is equivalent to 1 mile

This means that the initial distance <em>unit </em>used was ft while the final one was mile

Also, 1 hr/60 min denotes that;

1 hour is equivalent to 60 minutes.

This means that the initial time units used was hour while the final one was minute.

  • In conclusion, since we know the initial time and distance units used, we can say that the initial rate of speed ft/hr while final speed rate was miles/minutes.

Read more at; brainly.com/question/17734333

3 0
3 years ago
I really need help on this plz help me....​
Daniel [21]

Answer:

The correct answer is -12

4 0
3 years ago
If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (9-1(3)?
Anni [7]

Answer:

( g − f ) ( 3 ) = 23

Step-by-step explanation:

(g-f)(x)=g(x)-f(x)

=6x-(4-X(2))

=x(2)+6x-4

to evaluate (g-f) (#) substitute x=3 into (g-f)(x)

(g-f)=(9)+(6 x 3) -4=23

8 0
4 years ago
X^2+6x-6=0 rewritten by completing the square
Pie

Hello from MrBillDoesMath!

Answer:

(x+3)^2 -15 = 0



Discussion:

To complete the square add (and then subtract) the square of one-half the coefficient of x:


x^2 + 6x -6 = 0 =>

                 -- complete the square part --

x^2 + 6x +   (6/2)^2 - (6/2)^2                    - 6 = 0 =>

x^2 + 6x + 9 - 9 - 6 = 0 =>                                               as 6/2 = 3

(x + 3)^ 2      - 9  - 6 = 0 =>                                    

(x+3)^2 -15 = 0

We can solve this as follows:

(x+3)^2 = 15                                               take square root of both sides

(x+3) = +\- sqrt(15)

x = -3 +\- sqrt(15)


Thank you,

MrB

4 0
3 years ago
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