Answer:
6s⁹t³
Step-by-step explanation:
6s⁵t ₓ s⁴t² =
= 6ₓs⁵⁺⁴t¹⁺²
= 6s⁹t³
Your answer will be
-21h-56
H=2
Answer:
Yes the probability of getting at least one airplane from two boxes is 3/4 which is greater than 0.5.
Step-by-step explanation:
The probability of getting at least one aeroplane is calculated by = 1 -(P(not aeroplane from 1st box) P (not aeroplane from 2nd box))
P(at least one aeroplane)= 1- {P(not aeroplane)P(not aeroplane)}
Suppose there is one helicopter and one aeroplane in each box so
P(at least one aeroplane)= 1- {(1/2) (1/2))}
P(at least one aeroplane)= 1- 1/4
P(at least one aeroplane)= 3/4 > 0.5
So the probability of getting at least one airplane from two boxes is 3/4 which is greater than 0.5