Your choices are correct.
1. adding -3 to the function shifts its graph downward by 3 units.
2. 7^(2x) = (7^2)^x = 49^x
3. f(0) = -6; g(0) = -3, f(0) = 2×g(0)
R=i/pt
R=16/200*2=0.04*100=4%
To know whether the shape is the pre-image or the resulting shape, we need to look at its name.
In this instance, the name of the pre-image is GHIJ.
The resulting name of the shape would be G'H'I'J'.
An apostrophe is placed after every letter to signify that it is the resulting coordinate of the original.
