The least common denominator would be 56. Hope I helped you!
Answer:

Step-by-step explanation:
Average length 
Standard deviation 
Sample size 
Generally The point estimate for the mean length of all bolts in inventory is


This is an example of "a stratified sample".
<u>Answer:</u> Option B
<u>Explanation:</u>
A group-based sampling process that can be divided into subpopulations. For statistical studies, testing of each subpopulation separately may be useful if subpopulations within a total population differ, thus understood as "Stratified sampling".
One might, for instance, divide a adults sample into subgroups in terms of age, like 18 to 29, 30 to 39, 40 to 49, 50–59 etc with decided age difference as needed. A stratified sample may be more accurate than an easy sample of the similar size by random. As it offers more accuracy, a stratified sample sometimes involves a smaller sample, saving money.
Answer:
6/8
Step-by-step explanation:
2/8 + 2/8 + 2/8 = 6/8.
Add the tops. Hope this helps :)
I would solve this using tangents. Let h be height of flagpole.
Set up 2 right triangles, each with a base of 40.
The larger triangle has height of "h+70"
Smaller triangle has height of 70.
Now write the tangent ratios:

Note: A-B = 9
To solve for h we need to use the "Difference Angle" formula for Tangent

Plug in what we know:


