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butalik [34]
3 years ago
9

Please i need a quick help with this question plz

Mathematics
1 answer:
Vadim26 [7]3 years ago
4 0
257000cm^2 is the solution I think
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Barack walks 2 kilometers south and then x kilometers east. ​ ​He ends 5 kilometers away from his starting position. ​ ​ Find x
amid [387]

Answer:

4.6 km

Step-by-step explanation:

-This is a Pythagorean Theorem problem where the distances walked are effectively the base and height of the imaginary right triangle thereof.

#Apply Pythagorean theorem to solve:

b^2+h^2=H^2\\\\2^2+x^2=5^2\\\\x^2=5^2-2^2=21\\\\x=\sqrt{21}\\\\x=4.58\  km

\approx 4.6\ km

Hence, the distance x is 4.6 km

7 0
2 years ago
Sin(theta)+cos(theta)=0 what is theta? 20 points someone please help (A-Level pure maths)
Bumek [7]

Answer:

sin(theta) + cos(theta) = 0

sin(theta) = -cos(theta)

sin(theta)/cos(theta) = -1

tan(theta) = -1

theta = - 45° ± k·180°

8 0
3 years ago
(04.01) Which point could be removed in order to make the relation a function? (4 points) {(0, 2), (3, 8), (−4, −2), (3, −6), (−
umka21 [38]
A function will not have any repeating x values...it can have repeating y values, just not the x ones

{(0,2),(3,8),(-4,-2),(3,-6),(-1,8),(8,3)}
u would have to remove one of the sets of points that has 3 as its x value....so either remove (3,8) or (3,-6)....because with both of them in there, u have repeating x values
7 0
3 years ago
Read 2 more answers
What is 1.1865 rounded to the nearest cent.​
Artyom0805 [142]
Rounded to the nearest cent, the answer is 1.19
6 0
3 years ago
) How many kilowatt hours would the model predict on a day that has 14 hours of possible daylight?
eimsori [14]

Question:

A solar power company is trying to correlate the total possible hours of daylight (simply the time from sunrise to sunset) on a given day to the production from solar panels on a residential unit. They created a scatter plot for one such unit over the span of five months. The scatter plot is shown below. The equation line of best fit for this bivariate data set was: y = 2.26x + 20.01

How many kilowatt hours would the model predict on a day that has 14 hours of possible daylight?

Answer:

51.65 kilowatt hours

Step-by-step explanation:

We are given the equation line of best fit for this data as:

y = 2.26x + 20.01

On a day that has 14 hours of possible daylight, the model prediction will be calculated as follow:

Let x = 14 in the equation.

Therefore,

y = 2.26x + 20.01

y = 2.26(14) + 20.01

y = 31.64 + 20.01

y = 51.65

On a day that has 14 hours of daylight, the model would predict 51.65 kilowatt hours

8 0
3 years ago
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