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alexandr1967 [171]
3 years ago
8

What is the approximate area of a circle with a radius of 26 feet

Mathematics
1 answer:
My name is Ann [436]3 years ago
3 0
The area of a circle with a radius of 26 would be <span>2123.72 ft.</span>
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Please help ASAP!! Super appreciated!!! &lt;3
Vedmedyk [2.9K]
The data is not linear. From (3, 1) to (7, 2), we add 4 to the x-value and add 1 to the y-value. This pattern continues for a little while, however, from (11, 3) to (18, 5), we add only 7 to the x-value even though we added 2 to the y-value. Given this information, we can determine that this is not linear data.
5 0
3 years ago
Help i’m confused i don’t know what to do
VMariaS [17]

Answer:

-84i - 12i

Step-by-step explanation:

The distributive property is: a(b+c) = ab + ac

In this case, we have -6i(-14i+2)

-6i = a

-14i = b

2 = c

-6i(-14i+2) = -6i(-14i) + -6i(2)

= 84i^2 - 12i

= -84 - 12i

7 0
2 years ago
Read 2 more answers
Please help! will give brainliest:)
Lorico [155]
Answer

1) x = 8

2) x = 1/3y + -5/3z

3) x = -1/2y + -3/4z + -1/2

Hope this helps:))
7 0
2 years ago
(Q7) Determine the graph of the polar equation r = 12/6+4 cos theta.
masya89 [10]
ANSWER

b.

EXPLANATION

The given polar equation is,

r = \frac{12}{6 + 4 \cos( \theta) }

Cross multiply to get,

r(6 + 4 \cos( \theta) ) = 12

6r + 4r\cos( \theta) ) = 12

Substitute,

r\cos( \theta) = x

and

r = \sqrt{ {x}^{2} + {y}^{2} }

6 \sqrt{ {x}^{2} + {y}^{2} } + 4x = 12

3\sqrt{ {x}^{2} + {y}^{2} } + 2x = 6

3\sqrt{ {x}^{2} + {y}^{2} } = 4 - 2x

9({x}^{2} + {y}^{2}) =( 4 - 2x ) ^{2}

9{x}^{2} + 9 {y}^{2} =16 - 16x + 4x ^{2}

5{x}^{2} + 9 {y}^{2} + 16x = 16

This is an ellipse whose center is shifted to the left with orientation on the x-axis

The correct choice is B.

8 0
3 years ago
Need help on these three. thanks:))
Anton [14]
1. 0.3% or 30%
2. 15 minutes
3. 48 times
4 0
3 years ago
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