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3 years ago

What is the approximate area of a circle with a radius of 26 feet

Mathematics

1 answer:

My name is Ann [436]3 years ago

3 0

The area of a circle with a radius of 26 would be <span>2123.72 ft.</span>

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Please help ASAP!! Super appreciated!!! <3

Vedmedyk [2.9K]

The data is not linear. From (3, 1) to (7, 2), we add 4 to the x-value and add 1 to the y-value. This pattern continues for a little while, however, from (11, 3) to (18, 5), we add only 7 to the x-value even though we added 2 to the y-value. Given this information, we can determine that this is not linear data.

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3 years ago

Help i’m confused i don’t know what to do

VMariaS [17]

Answer:

-84i - 12i

Step-by-step explanation:

The distributive property is: a(b+c) = ab + ac

In this case, we have -6i(-14i+2)

-6i = a

-14i = b

2 = c

-6i(-14i+2) = -6i(-14i) + -6i(2)

= 84i^2 - 12i

= -84 - 12i

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2 years ago

Read 2 more answers

Please help! will give brainliest:)

Lorico [155]

Answer

1) x = 8

2) x = 1/3y + -5/3z

3) x = -1/2y + -3/4z + -1/2

Hope this helps:))

7 0

2 years ago

(Q7) Determine the graph of the polar equation r = 12/6+4 cos theta.

masya89 [10]

ANSWER

b.

EXPLANATION

The given polar equation is,

$r = \frac{12}{6 + 4 \cos( \theta) }$

Cross multiply to get,

$r(6 + 4 \cos( \theta) ) = 12$

$6r + 4r\cos( \theta) ) = 12$

Substitute,

$r\cos( \theta) = x$

and

$r = \sqrt{ {x}^{2} + {y}^{2} }$

$6 \sqrt{ {x}^{2} + {y}^{2} } + 4x = 12$

$3\sqrt{ {x}^{2} + {y}^{2} } + 2x = 6$

$3\sqrt{ {x}^{2} + {y}^{2} } = 4 - 2x$

$9({x}^{2} + {y}^{2}) =( 4 - 2x ) ^{2}$

$9{x}^{2} + 9 {y}^{2} =16 - 16x + 4x ^{2}$

$5{x}^{2} + 9 {y}^{2} + 16x = 16$

This is an ellipse whose center is shifted to the left with orientation on the x-axis

The correct choice is B.

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3 years ago

Need help on these three. thanks:))

Anton [14]

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3 years ago