All categories

3 years ago

3 in. 1 in. 2 in. 4 in.

Mathematics

1 answer:

notka56 [123]3 years ago

8 0

Answer:

The volume would be 12 inches.

Step-by-step explanation:

Volume is LxWxH

for the lower box, I did

4x2x1=8

For the top half

2x2x1=4

Then i added them together

8+4= 12

You might be interested in

40.) Decompose 7/8 into the sum of unit fractions.

Paraphin [41]

Answer:

7/8 = 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8

7/8 = 1/8 + 6/8

7/8 = 4/8 + 3/8

7/8 = 5/8 + 2/8

Step-by-step explanation:

Hope it helps!

4 0

4 years ago

One final question, what would be the proper way to write this? I thought it was the last one answer but I’m not sure

lina2011 [118]

Answer:

OMG NO- KEEP IT THAT WAY

You're already right! :)

3 0

3 years ago

Find the area of the trapezoid

Shalnov [3]

Answer: 8

Step-by-step explanation: so we can count the middle four, then the sides are basically two triangles that are the same, so we put them together and you get 4 more, so 4 plus 4 is 8

7 0

3 years ago

A new post-surgical treatment is being compared with a standard treatment. Seven subjects receive the new treatment, while seven

a_sh-v [17]

Answer:

$(17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745$

$(17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255$

Step-by-step explanation:

For this case we have the following info given:

Treatment: 12 13 15 19 20 21 24

Control: 18 23 24 30 32 35 39

We can find the sample mean and deviations with the the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s =\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}$

And repaplacing we got:

$\bar X_T = 17.714$ the sample mean for treatment

$\bar X_C = 28.714$ the sample mean for treatment

$s_T= 4.461$ the sample deviation for treatment

$s_C= 7.387$ the sample deviation for control

$n_T= n_C= 7$ the sample size for each sample

The degrees of freedom are given by:

$df= 7+7-2= 12$

The confidence interval for the difference of means is given by:

$(\bar X_T -\bar X_C) \pm t_{\alpha/2} \sqrt{\frac{s^2_T}{n_T} +\frac{s^2_C}{n_C}}$

The confidence is 98% so then the significance is $\alpha=0.02$ and $\alpha/2 =0.01$ . Then the critical value would be:

$t_{\alpha/2}=2.681$

And replacing we got:

$(17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745$

$(17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255$

4 0

4 years ago

Llana [10]

Answer:

Step-by-step explanation:

If the first floor of the Willis Tower is 21 feet high. and each additional floor is 12 feet high, then the floor heights as we move from one floor to another we keep increasing by 12feets and forms an arithmetic progression as shown;

21, (21+12), (21+12+12), ...

21, 33, 45...

a) To write an equation for the nth floor of the tower, we will have to find the nth term of the sequence using the formula for finding the nth term of an arithmetic sequence.

The nth term of an arithmetic sequence is expressed as $T_n = a + (n-1)d$