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3 years ago

What is the general form of the equation of the given circle with its center at A

Mathematics

1 answer:

BabaBlast [244]3 years ago

7 0

General form of circle with center at C(a,b) and radius r is

(x-a)^2 + (y-b)^2 = r^2. Here,

(x-(-3))^2 + (y-12)^2 = 5^2, or (x+3)^2 + (y-12)^2 = 25

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Find the volume of the rectangular prism<br> Thank you!!

Brrunno [24]

Answer:90

Step-by-step explanation: do length x base x height to get your answer

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2 years ago

Solve for x.<br> 3(2x + 5) = 33

Umnica [9.8K]

Answer:

x = 3

Step-by-step explanation:

3(2x + 5) = 33

3 * 2x + 3 * 5 = 33

6x + 15 = 33

6x = 33 - 15

x = 18 / 6

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2 years ago

A band to played 3 concerts and earned about a total of $321.00.the band earned about the same amount for each concert estimate

Darya [45]

All you have to do is divide 321 by 3 to get $107.00 each night

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2 years ago

Read 2 more answers

PLEASE HELP:))))))) 15points

Zielflug [23.3K]

Answer:7 cm

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Divide 44 by 2pi. Then u have your radius which is 7

7 0

2 years ago

HELP PLEASE!!! 10 PTS!!

allsm [11]

Answer:

m∠DEC = 78°

Step-by-step explanation:

Given information: AC = AD, AB⊥BD, m∠DAC = 44° and CE bisects ∠ACD.

If two sides of a triangles are congruent then the opposite angles of congruent sides are congruent.

AC = AD (Given)

$\angle ADC\cong \angle ACD$

$m\angle ADC=m\angle ACD$

According to the angle sum property, the sum of interior angles of a triangle is 180°.

$m\angle ADC+m\angle ACD+m\angle DAC=180$

$m\angle ACD+m\angle ACD+44=180$

$2m\angle ACD=180-44$

$2m\angle ACD=136$

Divide both sides by 2.

$m\angle ACD=68$

CE bisects ∠ACD.

$m\angle ACE=m\angle DCE=\dfrac{\angle ACD}{2}$

$m\angle ACE=m\angle DCE=\dfrac{68}{2}$

$m\angle ACE=m\angle DCE=34$

Use angle sum property in triangle CDE,

$m\angle CDE+m\angle DCE+m\angle DEC=180$

$68+34+m\angle DEC=180$

$102+m\angle DEC=180$

Subtract 102 from both sides.

$m\angle DEC=180-102$

$m\angle DEC=78$

Therefore, the measure of angle DEC is 78°.

6 0

2 years ago