Answer:
B
Step-by-step explanation:
![~~~2x^{16} - 32x^4\\\\ = 2x^4(x^{12} -16)\\\\=2x^4\left[(x^6)^2 - 4^2 \right]\\\\=2x^4(x^6 -4)(x^6 +4)~~~~~~~~~~~~~~~~~~;[a^2 -b^2 = (a+b)(a-b)]\\\\=2x^4\left[(x^3)^2 - 2^2\right] (x^6 +4)\\\\=2x^4(x^3 -2)(x^3 +2)(x^6 +4)](https://tex.z-dn.net/?f=~~~2x%5E%7B16%7D%20-%2032x%5E4%5C%5C%5C%5C%20%3D%202x%5E4%28x%5E%7B12%7D%20-16%29%5C%5C%5C%5C%3D2x%5E4%5Cleft%5B%28x%5E6%29%5E2%20-%204%5E2%20%5Cright%5D%5C%5C%5C%5C%3D2x%5E4%28x%5E6%20-4%29%28x%5E6%20%2B4%29~~~~~~~~~~~~~~~~~~%3B%5Ba%5E2%20-b%5E2%20%3D%20%28a%2Bb%29%28a-b%29%5D%5C%5C%5C%5C%3D2x%5E4%5Cleft%5B%28x%5E3%29%5E2%20-%202%5E2%5Cright%5D%20%28x%5E6%20%2B4%29%5C%5C%5C%5C%3D2x%5E4%28x%5E3%20-2%29%28x%5E3%20%2B2%29%28x%5E6%20%2B4%29)
If the larger angle is x and the smaller angle is y, y=(1/2)x+30 since it's 30 more than 1/2 of it. In addition, x+y=180 since they are supplementary. Plugging y=(1/2)x+30 into that, we get x+x/2+30=180=1.5x+30. Subtracting 30 from both sides, we get 1.5x=150. Next, we can divide both sides by 1.5 to get x=100 and y=(1/2)*100+30=50+30=80
Debit is where you have to pay extra when you use it. Credit doesn't!!!!!
-1, -8
0, -9
1, -10
2, -11
Hope that helps!
Since 
(density = mass/volume), we can get the mass/weight of the liquid by integrating the density 
over the interior of the tank. This is done with the integral
which is more readily computed in cylindrical coordinates as
