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2 years ago

Pls help meeeee This is about to be due

Mathematics

1 answer:

telo118 [61]2 years ago

4 0

Answer:

3:123 4:0 5:13.69

Step-by-step explanation:

I hope this helps

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What is the vaule of m in this equation 188 = m + 80

Crazy boy [7]

Explanation:

First, switch sides of an equation.

$m+80=188$

Then, you subtract by the 80 from both sides of an equation.

$m+80-80=188-80$

And finally, simplify and subtract the numbers.

$188-80=108$

$\boxed{m=108}$

Hope this helps!

Thank you!

Have a great day!

8 0

2 years ago

Read 2 more answers

Solve the system using elimination: Help me please 12x - 8y = -12 6x + 4y = -30

LUCKY_DIMON [66]

12x - 8y = -12

6x + 4y = -30

Multiply the 2nd equation by 2, to make the Y coefficients opposite:

6x + 4y = -30 x 2 = 12x + 8y = -60

Now add the two equations:

12x -8y = -12 + 12x +8y = -60

= 24x = -72

Divide bothe sides by 24 to solve for x:

x = -72/24

x = -3

Now replace x with -3 in the first equation to solve for y:

12(-3) - 8y = -12

-36 - 8y = -12

Add 36 to each side:

-8y = 24

Divide both sides by -8 to solve for y:

y = 24 / -8

y = -3

X = -3 and y = -3

(-3,-3)

4 0

3 years ago

A giant bamboo plant grew an average of 18 centimeters per year the botanist started measuring the plant when it was 5 centimete

Yanka [14]

The answer to your question would be
Height=5cm+
(18cm)*(y)

4 0

3 years ago

100 POINTS AND BRAINLIEST

zysi [14]

Answer:

8 square units and $\frac{40}{3}$ square units

Step-by-step explanation:

The area of the triangle ABC is 24 square units.

1. Triangles ABC and FBG are similar with scale factor $\frac{1}{3},$ then

$\dfrac{A_{\triangle FBG}}{A_{\triangle ABC}}=\dfrac{1}{9}\Rightarrow A_{\triangle FBG}=\dfrac{1}{9}\cdot 24=\dfrac{8}{3}\ un^2.$

2. Triangles ABC and DBE are similar with scale factor $\frac{2}{3},$ then

$\dfrac{A_{\triangle DBE}}{A_{\triangle ABC}}=\dfrac{4}{9}\Rightarrow A_{\triangle DBE}=\dfrac{4}{9}\cdot 24=\dfrac{32}{3}\ un^2.$

3. Thus, the area of the quadrilateral DFGE is

$A_{DFGE}=A_{\triangle DBE}-A_{\triangle FBG}=\dfrac{32}{3}-\dfrac{8}{3}=8\ un^2.$

and the area of the quadrilateral ADEC is

$A_{ADEC}=A_{\triangle ABC}-A_{\triangle DBE}=24-\dfrac{32}{3}=\dfrac{40}{3}\ un^2.$

4 0

3 years ago

Read 2 more answers

P(x) = 3x - 7; Q(x) = -4x + 3

bulgar [2K]

Answer:

qasdddddfghjklkmnbvcxzaqwertyuioikjhgbvfcxdgfcgvhgyjfthdgfcvnbhnjkhbjgcfd b

8 0

3 years ago