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cricket20 [7]
3 years ago
6

Please helppppp !!!!!!!!!!! Will mark correct Brianliest !!!!!!!!!!!!!!

Mathematics
1 answer:
Mice21 [21]3 years ago
8 0

Answer:

the third side is \sqrt{85}

Step-by-step explanation:

root 85 is already the simplest form

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Anuta_ua [19.1K]

Answer:

A 161 square feet

Step-by-step explanation:

5×5=25

1/2 of 25 is 12.5(triangular face) ×2=25

5×8 is 40 (base and left face)

8×7 is 56 (right face)

25+40+40+56=161

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3 years ago
On circle O below, the measure of SV is 120°.<br><br><br>What is the measure of VU?<br>​
DochEvi [55]

Answer: Angle VU is 44 degrees

Step-by-step explanation:

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3 years ago
I WILL GIVE YOU BRAINLIEST IF YOU HELP me
ELEN [110]

Answer:

( 1 , 6 )

Step-by-step explanation:

sory if it is wrong

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3 years ago
5. Jack and Jill use rain gauges that are the same size and shape to measure rain on top of a hill. Jack
GREYUIT [131]

Answer:

List the multiples

1/4,2/4,3/4,4/4

1/8,2/8,3/8,4/8,5/8,6/8,7/8,8/8

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2/4=4/8

4/4=8/8

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Step-by-step explanation:

7 0
3 years ago
Timothy built a base for a circular tabletop. The base can support a tabletop with a radius of at least 6 inches, but not more t
neonofarm [45]

Let

r------> the radius of the circular tabletop

we know that

r\geq 6\ in

r\leq23\ in

so

6\ in \leq r \leq 23\ in

The area of a circle is equal to

A=\pi r^{2}

where

r is the radius of the circle

<u>Part a)</u> What is the smallest possible area of the tabletop that will fit on Timothy’s table base?

we know that

the smallest possible area of the tabletop is for r=6\ in

Substitute the value  of r in the formula

A=\pi 6^{2}

A=113.09\ in^{2}

Round to the nearest whole square inch

so

A=113\ in^{2}

therefore

<u>the answer part a) is </u>

the smallest possible area of the tabletop is 113\ in^{2}

<u>Part b)</u> What is the largest possible area of the tabletop that will fit on Timothy’s table base?

we know that

the largest possible area of the tabletop is for r=23\ in

Substitute the value  of r in the formula

A=\pi 23^{2}

A=1,661.90\ in^{2}

Round to the nearest whole square inch

so

A=1,662\ in^{2}

therefore

<u>the answer part b) is </u>

the largest possible area of the tabletop is 1,662\ in^{2}

7 0
4 years ago
Read 2 more answers
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