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2 years ago

Hola alguien me podría ayudar con este problema :< porfa

Mathematics

1 answer:

nevsk [136]2 years ago

7 0

Answer:

8= 24b

8/8=24b/8

b=3

Step-by-step explanation:

Based on my own learning

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Identify the constant of proportionality from the graph. 11 10 9 00 7 6 5 1 2 3 4 5 6 7 8 9 10 11 O A. 4 B. 8 O c. D. 3

mafiozo [28]

Answer:

A. 4

Step-by-step explanation:

Constant of proportionality (k) = y/x

We can use the coordinates of any point on the line to find k.

Let's use (2, 8)

Constant of proportionality (k) = 8/2

Constant of proportionality (k) = 4

4 0

3 years ago

Let f be continuous on [0, a] and differentiable on (0, a), Prove that if f(a)=0 then there is at least one value of x in (0, a)

asambeis [7]

Answer:

See picture attached

Step-by-step explanation:

6 0

3 years ago

Can someone PLEASE help me :((

Mars2501 [29]

I think is inside and then outside. Not sure

Hope this helps!

6 0

3 years ago

How to prove this???

swat32

$\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 
$

go to right side now

$4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)$

use $x^3 - y^3 = (x-y)(x^2 + xy + y^2)$ and $x^3 + y^3 = x^2 - xy + y^2$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)$

so $\sin^2 A + \cos^2 A = 1$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
 \Rightarrow Left hand side$

4 0

3 years ago

For each function, do the following: a) state the name of the function, b) identify the independent and dependent variable, c) i

daser333 [38]

<h2>Hello</h2>

The answers are:

a) The name of the function is g, and it's an Exponential Function.

b) Independent variable : x , dependent variable : g(x)/y

c) The rule that assigns exactly one output to the very input is called "function".

d) $g(4)=2^{4}+12=16+12=28$

Usually, the name of a function (g(x)) is given by letter that is out of the parentheses. For this exercise, the name of the function is "g", and it's an Exponential Function.

The independent variable of a function is the variable we assign the different values. For this exercise, the independent variable is designated with the letter "x".

The dependent variable is the function itself (g(x)), it's also called "y", and it's called "dependent" variable because its values will always depend on the "independent variable".

A function is the rule that states that there is exactly one output (range value) to the each input (domain value). A function only exists when there is exactly one output value (range) for each input (domain), if there is more than one output for each input, the function does not exist.

To evaluate a function we need to assign values to the independent variable(x), therefore:

$g(4)=2^{4}+12=16+12=28$

Have a nice day!

8 0

3 years ago

Hola alguien me podría ayudar con este problema :< porfa ​

Hola alguien me podría ayudar con este problema :< porfa