A cereal bar contains 4000 milligrams of protein. How much protein does it contain in grams

There are 785 students in the senior class. If there are 77 more females in the class than males, how many male and female senio

VLD [36.1K]

There are 431 females

785-77=708
708/2=354
354=males
354+77=431
431=females
to check work do 431=354 and that equals 785

5 0

3 years ago

The sum of the number is -44.84 one of the numbers is 24.6 the other two numbers are equal to eat other what is the value of eac

nikklg [1K]

The answer is -34.72. I have attached a picture of the work. I hope this helps. :)

3 0

4 years ago

I NEED HELP!!!! I am currently reviewing for my last test, and i am struggling with this problem. I KNOW WHAT THE ANSWER IS BUT

stira [4]

Answer:

$336\:\mathrm{ft^2}$

Step-by-step explanation:

The total surface area simply consists of three rectangles and two triangles. To find the total surface of the figure, find the sum of each of the shapes that make up the outside of the figure:

2 triangles: 2 x 1/2 x 6 x 8 = 48 ft^2

First rectangle: 6 x 12 = 72 ft^2

Second rectangle: 8 x 12 = 96 ft^2

Third rectangle: 10 x 12 = 120 ft^2

*Note: One of the dimensions is in yards, so make sure to convert it to ft (1 yd = 3ft)

Thus, the total surface area of the figure is 48+72+96+120 = 336 ft^2.

4 0

3 years ago

What is the slope of the line of (18, 28 ) (6,8)?

Finger [1]

Answer:

5/3

Step-by-step explanation:

to find the slope, we have to use the formula y2-y1 over x2-x1. Now, plug in our values; 8-28 over 6-18. Our answer becomes -20 over -12 this simplifies to 5 over 3, and there's your answer.

4 0

3 years ago

All 4 questions please

scZoUnD [109]

Answer:

π = S/2πrh
v = √2E/m
b = (-7a+c)/2
x =3y-1

Step-by-step explanation:

1.

$S = 2\pi rh\\Divide\:both\sides\:of\:the\:equation\:by\:2rh\\\\\frac{S}{2rh} = \frac{2 \pi rh}{2 rh} \\\\\pi = \frac{S}{2rh}$

2.

$E = \frac{1}{2} mv^2\\\\E = \frac{mv^2}{2} \\\\Cross\:multiply\\\\2E =mv^2\\Divide\:both\:sides\:of\:the\:equation\:by\:m\\\frac{2E}{m} = \frac{mv^2}{m} \\\\\frac{2E}{m} =v^2\\Square\:root\:both\:sides\:of\:the\:equation\\\sqrt{\frac{2E}{m} } = \sqrt{v^2} \\\\\sqrt{\frac{2E}{m} } =v\\\\v =\sqrt{\frac{2E}{m} }$

3.

$7a+2b =c\\Isolate\:b\\\\2b =c-7a\\2b= -7a+c\\Divide\:both\:sides\:of\:the\:equation\:by \:2\\\frac{2b}{2} =\frac{-7a+c}{2} \\\\b = \frac{-7a+c}{2}$

4.

$y = \frac{1}{3} (x+1)\\\\y = \frac{x+1}{3}\\\\Cross\:multiply \\3y =x+1\\Isolate \:x\\3y -1=x\\\\x =3y-1$

7 0

3 years ago