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rjkz [21]
3 years ago
8

I need help with this question plz

Mathematics
2 answers:
Ivahew [28]3 years ago
8 0

Answer:

22/35

Step-by-step explanation:

you make 1 4/7 into an improper fraction 11/7 then multiply by 2/5 you get 22/35.

morpeh [17]3 years ago
7 0

Answer:

\frac{22}{ 35}

Step-by-step explanation:

1 4/7= 11/7

11/7×2/5=22/35

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1. Write the linear equation for a line with a slope of 1/2 that goes through the point (-1,<br> 0).
svetlana [45]

Answer:

uhuhhubuggyugyug

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Step-by-step explanation:

y7gukgyfkjiyfikyutgikuygtujki

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2 years ago
Need help due tonight!!
Luba_88 [7]

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64

Step-by-step explanation:

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2 years ago
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Use the Fundamental Theorem for Line Integrals to find Z C y cos(xy)dx + (x cos(xy) − zeyz)dy − yeyzdz, where C is the curve giv
Harrizon [31]

Answer:

The Line integral is π/2.

Step-by-step explanation:

We have to find a funtion f such that its gradient is (ycos(xy), x(cos(xy)-ze^(yz), -ye^(yz)). In other words:

f_x = ycos(xy)

f_y = xcos(xy) - ze^{yz}

f_z = -ye^{yz}

we can find the value of f using integration over each separate, variable. For example, if we integrate ycos(x,y) over the x variable (assuming y and z as constants), we should obtain any function like f plus a function h(y,z). We will use the substitution method. We call u(x) = xy. The derivate of u (in respect to x) is y, hence

\int{ycos(xy)} \, dx = \int cos(u) \, du = sen(u) + C = sen(xy) + C(y,z)  

(Remember that c is treated like a constant just for the x-variable).

This means that f(x,y,z) = sen(x,y)+C(y,z). The derivate of f respect to the y-variable is xcos(xy) + d/dy (C(y,z)) = xcos(x,y) - ye^{yz}. Then, the derivate of C respect to y is -ze^{yz}. To obtain C, we can integrate that expression over the y-variable using again the substitution method, this time calling u(y) = yz, and du = zdy.

\int {-ye^{yz}} \, dy = \int {-e^{u} \, dy} = -e^u +K = -e^{yz} + K(z)

Where, again, the constant of integration depends on Z.

As a result,

f(x,y,z) = cos(xy) - e^{yz} + K(z)

if we derivate f over z, we obtain

f_z(x,y,z) = -ye^{yz} + d/dz K(z)

That should be equal to -ye^(yz), hence the derivate of K(z) is 0 and, as a consecuence, K can be any constant. We can take K = 0. We obtain, therefore, that f(x,y,z) = cos(xy) - e^(yz)

The endpoints of the curve are r(0) = (0,0,1) and r(1) = (1,π/2,0). FOr the Fundamental Theorem for Line integrals, the integral of the gradient of f over C is f(c(1)) - f(c(0)) = f((0,0,1)) - f((1,π/2,0)) = (cos(0)-0e^(0))-(cos(π/2)-π/2e⁰) = 0-(-π/2) = π/2.

3 0
3 years ago
Cting Polynomials: Practice
Colt1911 [192]

The option that's true regarding the sum and difference of the polynomial p(x) and b is B. The sum and difference of p(x) and b are polynomials.

<h3>How to illustrate the information?</h3>

From the information given, it was stated that p(x) is a polynomial and is given as p(=) = a₁ + a₁ + a₂=² + ... + an.

In this case, it should be noted that the sum and difference of p(x) and b are polynomials.

They can't be integers as the function given is represented as a polynomial.

In conclusion, the correct option is B.

Learn more about polynomial on:

brainly.com/question/16340513

#SPJ1

7 0
1 year ago
What is an equation in point-slope form of the line that passes through the point (4,4) and has a slope of -5?
Nastasia [14]
(y - 4) = -5 (x - 4)
3 0
3 years ago
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