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Bond [772]
3 years ago
14

Chang knows one side of a triangle is 13cm which set of two sides is possible for the lengths of the other two sides of this tri

angle
Mathematics
1 answer:
Nikolay [14]3 years ago
4 0
Use the Pythagorean Theorem to check out these possibilities (which you really do need to share here).

Note that 13^2 = 12^2 + 5^2, so 12 and 5 are a possible set of side lengths here.

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1. What are two numbers that multiply to make -24 and sum to make -5?
charle [14.2K]
1) -8 and 3
because -8+3= -5 and -8x3=24
2) -8 and -5
because -8-5=-13 and -8x-5=40
8 0
3 years ago
What is the equation of the line that is parallel to y=3x+2 and goes through the points (5,8)?
ira [324]
Parallel lines has equal slopes.

Line y = 3x + 2 has a slope of 3.

Required equation is y - 8 = 3(x - 5)
y = 3x - 15 + 8
y = 3x - 7
6 0
3 years ago
Please help I am so lost!!!
ASHA 777 [7]
\bf tan\left( \frac{x}{2} \right)+\cfrac{1}{tan\left( \frac{x}{2} \right)}\\\\
-----------------------------\\\\
tan\left(\cfrac{{{ \theta}}}{2}\right)=
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\pm \sqrt{\cfrac{1-cos({{ \theta}})}{1+cos({{ \theta}})}}
\\ \quad \\

\cfrac{sin({{ \theta}})}{1+cos({{ \theta}})}
\\ \quad \\

\boxed{\cfrac{1-cos({{ \theta}})}{sin({{ \theta}})}}
\end{cases}\\\\

\bf -----------------------------\\\\
\cfrac{1-cos(x)}{sin(x)}+\cfrac{1}{\frac{1-cos(x)}{sin(x)}}\implies \cfrac{1-cos(x)}{sin(x)}+\cfrac{sin(x)}{1-cos(x)}
\\\\\\
\cfrac{[1-cos(x)]^2+sin^2(x)}{sin(x)[1-cos(x)]}\implies 
\cfrac{1-2cos(x)+\boxed{cos^2(x)+sin^2(x)}}{sin(x)[1-cos(x)]}
\\\\\\
\cfrac{1-2cos(x)+\boxed{1}}{sin(x)[1-cos(x)]}\implies \cfrac{2-2cos(x)}{sin(x)[1-cos(x)]}
\\\\\\
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4 0
3 years ago
5(4x + 2) ÷ 7y
murzikaleks [220]

Answer:

5 = term

sum = +

product = x or * (times)

4 = coefficent

quotient = division symbol

factor = 2

Step-by-step explanation:

6 0
3 years ago
The waiting time at an elevator is uniformly distributed between 30 and 200 seconds. What is the probability a rider must wait b
serg [7]

Answer:

17.65% probability a rider must wait between 1 minute and 1.5 minutes

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is between c and d is given by the following formula

P(c \leq X \leq d) = \frac{d - c}{b - a}

For this problem, we have that:

a = 30, b = 200, c = 1*60 = 60, d = 1.5*60 = 90

P(60 \leq X \leq 90) = \frac{90 - 60}{200 - 30} = 0.1765

17.65% probability a rider must wait between 1 minute and 1.5 minutes

7 0
3 years ago
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