All categories

3 years ago

When finding the perimeter of a circle and half circle, what's the usual formula?

Mathematics

2 answers:

d1i1m1o1n [39]3 years ago

6 0

Or an easier way is 2* pi* r(radius)

Shkiper50 [21]3 years ago

4 0

Answer:

The perimeter of a semicircle includes the arc and the diameter. Here are some formulas that you can use.

Step-by-step explanation:

P = C / 2 + d

where C is the circumference of the whole circle

P = π r + 2r

where r is the radius

P = (2 + π) r

P = (d π / 2) + d

P = d π / 2 + 2 d / 2

P = (d π + 2 d) / 2

P = (2 + π) d / 2

Found at this website here: https://www.quora.com/What-is-the-formula-for-the-perimeter-of-a-semicircle

Hope this Helped! Good Luck!

You might be interested in

The kicker on the football team made 8 out of 9 of his field goals. about what percent of field goals did the kicker miss

daser333 [38]

Answer:

11%

Step-by-step explanation:

if he made 8/9 attempts, that leaves 1/9 and 1/9 is .11 so its 11% that he missed

8 0

2 years ago

Read 2 more answers

18, 7 The LCM of 18 and 7 is

Korvikt [17]

Answer:

126

Step-by-step explanation:

Please mark me as brainlist

4 0

2 years ago

One of the rows in the table has an error and does not have the same ratio as the other rows. Which explains how to correct the

hram777 [196]

Row 1 3 ft 91.44 cm
The ratio is 91.44 cm/ 3 ft = 30.48 cm/ft

Row 2 6 ft 172.88 cm
The ratio is 172.88 cm / 6 ft = 28.81 cm/ft which ius not the same as 30.48 cm/ft.

Row 3 7 ft 213.36 cm

The ratio is 213.36 cm/ 7 ft = 30.48 cm/ft, which is the same as the first ratio.

Since 2 rows have the ratio 30.48 cm/ft, this ratio is correct. The ratio 172.88 cm / 6 ft is incorrect.

6 ft * 30.48 cm/ft = 182.88 cm

Answer: 
B.Row 2 should show 6 feet is equivalent to 182.88 centimeters.

4 0

3 years ago

Read 2 more answers

Find the length of the curve y = integral from 1 to x of sqrt(t^3-1)

Arlecino [84]

$y=\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt$

By the fundamental theorem of calculus,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm d}{\mathrm dx}\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt=\sqrt{x^3-1}$

Now the arc length over an arbitrary interval $(a,b)$ is

$\displaystyle\int_a^b\sqrt{1+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx=\int_a^b\sqrt{1+x^3-1}\,\mathrm dx=\int_a^bx^{3/2}\,\mathrm dx$

But before we compute the integral, first we need to make sure the integrand exists over it. $x^{3/2}$ is undefined if $x$ , so we assume $a\ge0$ and for convenience that $a$ . Then

$\displaystyle\int_a^bx^{3/2}\,\mathrm dx=\frac25x^{5/2}\bigg|_{x=a}^{x=b}=\frac25\left(b^{5/2}-a^{5/2}\right)$

6 0

3 years ago

A dog walker earns $10 plus $3 per dog. What equation represents this model?

xxTIMURxx [149]

10+3x Or 3x+10.
This is because he gets 10 dollars add it to the 3 he gets per dog. The per dog is X as you don’t know how many dogs he gets

6 0

2 years ago

When finding the perimeter of a circle and half circle, what's the usual formula? ​

When finding the perimeter of a circle and half circle, what's the usual formula?