$33 Because if she works three hours and each hours she gets three dollars the that is 9 dollars plus 12 5 and 7 equals 33
Answer:
See below :)
Step-by-step explanation:
Hello,
So at the bottom, it says "Give lables or the x-axis and the y-axis as it relates to the situtation"
Labels are the things that show what each part of the graph means. See picture I uploaded after reading my explanation.
We first want to find out how (1, 1.5) relates to 3 tbs oil and 2 tbs vinegar
We want to find the same scale factor between the x and ys.
We can see that 1 is half of 2 and 1.5 is half 3 so we can say that,
Vinegar is the x
Oil is the y
Starting from the y-intercept of ![\displaystyle [0, 2],](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5B0%2C%202%5D%2C)
you do 
by either moving two blocks <em>north</em> over three blocks <em>west</em> or two blocks <em>south</em> over three blocks <em>east</em> [<em>west</em> and <em>south</em> are negatives].
I am joyous to assist you anytime.
Answer:
○ A. No, x = -6 is not a zero of the polynomial.
The quotient is x - 29, and the remainder is 234.
Step-by-step explanation:
[x - 3][x - 20] >> Factored Form
Obviously, this is not a zero. Now, to get the remainder, we have to plug in the vertical line of <em>x = -6</em> into its conjugate, meaning an expression with opposite signs, which is <em>x + 6</em>. This is the expression we divide the dividend by, so you will have this:
\frac{{x}^{2} - 23x - 60}{x + 6}
Since the divisor is in the form of <em>x - c</em>, using Synthetic Division, we get this:
x - 29 + \frac{234}{x + 6}
You see? You have <em>x - 29</em> in the quotient, and you have 234 as the numerator remainder.
I am joyous to assist you anytime.
-x^2+105x-1050=1550
We move all terms to the left:
-x^2+105x-1050-(1550)=0
We add all the numbers together, and all the variables
-1x^2+105x-2600=0
a = -1; b = 105; c = -2600;
Δ = b2-4ac
Δ = 1052-4·(-1)·(-2600)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
<span><span>x1</span>=<span><span>−b−<span>Δ√</span></span><span>2a</span></span></span><span><span>x2</span>=<span><span>−b+<span>Δ√</span></span><span>2a</span></span></span>
<span><span>Δ<span>−−</span>√</span>=<span>625<span>−−−</span>√</span>=25</span>
<span><span>x1</span>=<span><span>−b−<span>Δ√</span></span><span>2a</span></span>=<span><span>−(105)−25</span><span>2∗−1</span></span>=<span><span>−130</span><span>−2</span></span>=+65</span>
<span><span><span>x2</span>=<span><span>−b+<span>Δ√</span></span><span>2a</span></span>=<span><span>−(105)+25</span><span>2∗−1</span></span>=<span><span>−80</span><span>−2</span></span>=+40</span></span>
