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Nesterboy [21]
4 years ago
11

Does doubling the height of a cylinder have the same effect on the volume of a cylinder as doubling the radius? Explain.

Mathematics
2 answers:
Sindrei [870]4 years ago
5 0

Answer:

No, it does not have the same effect. Doubling the height of a cylinder doubles the volume, while doubling the radius generates a volume 4 times greater.

Pavlova-9 [17]4 years ago
4 0
Doubling the height only doubles the volume in one dimension.  So, doubling the height merely doubles the volume. 

Doubling the radius doubles the volume in two dimensions.  So, doubling the radius increases the volume by 2^2 (or 4) times.


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C. 2/3 is the answer.
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3 years ago
The usual life of a computer terminal at a university computer center is known to be normally distributed with a mean of 3.25 ye
UNO [17]

Answer:

a) 0.6915; b) 2.83 years

Step-by-step explanation:

For part a,

The formula for a z score is

z=\frac{X-\mu}{\sigma}

Our mean, μ, is 3.25 and our standard deviation, σ, is 0.5.

This gives us

z = (3-3.25)/0.5 = -0.25/0.5 = -0.5

Using a z table, we see that the area under the curve to the left of this is 0.3085.  However we want the area to the right; this means we subtract from 1:

1-0.3085 = 0.6915

For part b,

We look in the cells of a z table to find the value closest to 20%, or 0.2000.  This is 0.2005, which corresponds with a z score of -0.84:

-0.84 = (X-3.25)/0.5

Multiply both sides by 0.5:

0.5(-0.84) = ((X-3.25)/0.5)(0.5)

-0.42 = X-3.25

Add 3.25 to each side:

-0.42+3.25 = X-3.25+3.25

X = 2.83

The advertised life would be 2.83 years.

8 0
3 years ago
I am stuck on this question of my maths test.
V125BC [204]

Answer:

angle y

58 + 38 + y = 180 (angle sum property)

96 + y = 180

y = 180 - 96

y = 84

angle x

x = 29 (58/2)

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the values of x = 29 and y = 84

6 0
3 years ago
Ashley has 500 songs in his music player. Every week he adds 10 songs to his collection. How many songs will he have in his musi
joja [24]
500 (the current collection) + 10 (the weekly addition) x 20 (weeks to add)

500 + 10*20 (Multiplication comes before addition)

500+200

700
8 0
3 years ago
Read 2 more answers
Find the velocity and position vectors of a particle that has the given acceleration and the given initial velocity and position
stira [4]

Answer:

v(t) = (2t+1) \mathbb{i} +3t^2 \mathbb{j} +4t^3 \mathbb{k}

r(t) = (t^2+t) \mathbb{i} +(t^3+2) \mathbb{j} +(t^4 - 3) \mathbb{k}

Step-by-step explanation:

The velocity vector is the integral of the acceleration vector i.e.

v(t) = \int a(t) dt

v(t) = \int (2 \mathbb{i}+6t \mathbb{j} 12t^2 \mathbb{k}) dt

v(t) = 2t \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k} + C_1

When t=0, v(0) = \mathbb{i}. Inserting these values in v(t),

C_1= \mathbb{i}

v(t) = 2t \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k} + \mathbb{i}

v(t) = (2t+1) \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k}

The position vector is the integral of the velocity vector i.e.

r(t) = \int v(t) dt

r(t) = \int ((2t+1) \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k}) dt

r(t) = (t^2+t) \mathbb{i}+t^3 \mathbb{j} t^4 \mathbb{k} + C_2

When t=0, r(t) =2\mathbb{j}-3\mathbb{k}. Inserting these values in r(t),

C_2=2\mathbb{j}-3\mathbb{k}

r(t)= (t^2+t) \mathbb{i}+t^3 \mathbb{j}+ t^4 \mathbb{k} + 2\mathbb{j}-3\mathbb{k}

r(t) = (t^2+t) \mathbb{i}+(t^3+2) \mathbb{j}+ (t^4-3) \mathbb{k}

5 0
4 years ago
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