All categories

3 years ago

What is the simple rational expression for 10b + 100 ________ b + 10

Mathematics

2 answers:

PtichkaEL [24]3 years ago

4 0

Answer:

10 ( b+10)

Step-by-step explanation:

10 b + 100

Factor out a 10

10 * b + 10 * 10

10 ( b+ 10)

hope it helps !!!!

Alexandra [31]3 years ago

3 0

Answer:

10b + 100 _= 10(b + 10)

Step-by-step explanation:

find common factor for 10b and 100 and put it in front of ( )

divide each term by 10 and put answer inside ( )

You might be interested in

Help answer these 2 questions please!!! They are Inequality Sentences....

bearhunter [10]

Answer:

n divided by 12 < 1

9 < n - 3

Step-by-step explanation:

for the second equation the inequality symbol is the one with the line under it. my computer doesn't have that sorry

3 0

3 years ago

A Russian mathmatician named Christian Goldbach came up with a theory that every even number can be written as the sum of two od

belka [17]

1 + 5 = 6
3 + 3 = 6

3 + 47 = 50
7 + 43 = 50
13 + 37 = 50
19 + 31 = 50

4 0

3 years ago

15)

kykrilka [37]

Answer:

A) 2 cm

Step-by-step explanation:

The sum of two sides of a triangle must be greater than the third side

2 + 3 is not greater than 5

8 0

3 years ago

Read 2 more answers

What is the area of the triangle pls help

OLga [1]

Answer:

Area of a triangle =1/2bh.

1/2×8×10=40cm^2.

8 0

3 years ago

Suppose r⃗ (t)=cos(πt)i+sin(πt)j+5tkr→(t)=cos(πt)i+sin(πt)j+5tk represents the position of a particle on a helix, where zz is th

gtnhenbr [62]

Answer:

a) t = 4

b) v = pi j + 5 k

c) rt = 1i + (pi t) j + (20 +5t )k

Step-by-step explanation:

You have the following vector equation for the position of a particle:

$r(t)=cos(\pi t)\hat{i}+sin(\pi t)\hat{j}+5t\hat{k}$ (1)

(a) The height of the helix is given by the value of the third component of the position vector r, that is, the z-component.

For a height of 20 you have:

$5t=20\\\\t=\frac{20}{5}=4$

(b) The velocity of the particle is the derivative, in time, of the vector position:

$v(t)=\frac{dr(t)}{dt}=-\pi sin(\pi t)\hat{i}+\pi cos(\pi t)\hat{j}+5\hat{k}$ (2)

and for t=4 (height = 20):

$v(t=4)=-\pi sin(\pi (4))\hat{i}+\pi cos(\pi (4))\hat{j}+5\hat{k}\\\\v(t=4)=-0\hat{i}+\pi\hat{j}+5\hat{k}$

(c) The vector parametric equation of the tangent line is given by:

$r_t(t)=r_o+vt$ (3)

ro: position of the particle for t=4

$r_o=cos(\pi (4))\hat{i}+sin(\pi (4))\hat{j}+20\hat{k}\\\\r_o=\hat{i}+0\hat{j}+20\hat{k}$

Then you replace ro and v in the equation (3):

$r_t=(1\hat{i}+20\hat{k})+(\pi \hat{j}+5\hat{k})t\\\\r_t=1\hat{i}+\pi t \hat{j}+(20+5t)\hat{k}$

3 0

3 years ago