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saveliy_v [14]
3 years ago
7

What is the answer to the math problem 18 minus 4x = negative 2?

Mathematics
1 answer:
pentagon [3]3 years ago
3 0
The answer to this equation is 5.
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What is the solution to the inequality below? <br> square root x arrow pointing left 9
storchak [24]
If x is less than 81, then we get a solution, but x should also be larger than or equal to zero since radicands must be nonnegative, therefore,  <span>x<81.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
3 0
3 years ago
Which solids have a round base? Select two options.
nirvana33 [79]
Cone and cylinder both have round bases
6 0
1 year ago
Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)
GarryVolchara [31]

<u>Question 6</u>

1) \overline{AB} \cong \overline{BD}, \overline{CD} \perp \overline{BD}, O is the midpoint of \overline{BD}, \overline{AB} \cong \overline{CD} (given)

2) \angle ABO, \angle ODC are right angles (perpendicular lines form right angles)

3) \triangle ABO, \triangle CDO are right triangles (a triangle with a right angle is a right triangle)

4) \overline{BO} \cong \overline{OD} (a midpoint splits a segment into two congruent parts)

5) \triangle ABO \cong \triangle CDO (LL)

<u>Question 7</u>

1) \angle ADC, \angle BDC are right angles), \overline{AD} \cong \overline{BD}

2) \overline{CD} \cong \overline{CD} (reflexive property)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \triangle ADC \cong \triangle BDC (LL)

5) \overline{AC} \cong \overline{BC} (CPCTC)

<u>Question 8</u>

1) \overline{CD} \perp \overline{AB}, point D bisects \overline{AB} (given)

2) \angle CDA, \angle CDB are right angles (perpendicular lines form right angles)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \overline{AD} \cong \overline{DB} (definition of a bisector)

5) \overline{CD} \cong \overline{CD} (reflexive property)

6)  \triangle ADC \cong \triangle BDC (LL)

7) \angle ACD \cong \angle BCD (CPCTC)

8 0
2 years ago
Dollar is worth three and 3 1/2 kruneros. What is the value of 43 3/4 kruneros?
Korvikt [17]

<em><u>Question:</u></em>

One dollar is worth 3 1/2 kruneros. What is the value of 43 3/4 kruneros?

<em><u>Answer:</u></em>

The value of 43\frac{3}{4} kruneros is 12.5 dollars

<em><u>Solution:</u></em>

Given that,

Dollar is worth three and 3 1/2 kruneros

Which means,

1 \text{ dollar } = 3\frac{1}{2} \text{ kruneros }\\\\1 \text{ dollar } = 3.5 \text{ kruneros }

We have to find the value of 43\frac{3}{4} kruneros

Let us convert the mixed fractions to improper fractions

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator.

43\frac{3}{4} = \frac{43 \times 4 + 3}{4} = \frac{175}{4} = 43.75

So we have to find the value of 43.75 kruneros

Let "x" be the value of 43.75 kruneros

Then,

1 dollar = 3.5 kruneros

x dollar = 43.75 kruneros

This forms a proportion and we can solve the sum by cross multiply

1 \times 43.75 = x \times 3.5\\\\x = \frac{43.75}{3.5}\\\\x = 12.5

Thus value of 43\frac{3}{4} kruneros is 12.5 dollars

5 0
3 years ago
What is the slope for the line x+y = -3
andreev551 [17]

Answer:

The slope is -1.

Step-by-step explanation:

x+y=3: Put it in slope intercept form. First you have to subtract x from both sides: y=-3-x. Next switch into slope intercept form. y=-x-3. The slope is -x (or -1) and the y-intercept is -3.

5 0
2 years ago
Read 2 more answers
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