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Vlad [161]
2 years ago
10

NEEEEEEED HEEEEEEEELP !!!!!!!!!!!!!!!!! 13 POINTSSSSSS

Mathematics
2 answers:
drek231 [11]2 years ago
8 0

the answer will be thirty three cm.

maks197457 [2]2 years ago
5 0
If I’m not mistaken it should be 38 cm if I’m wrong I’m sorry
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Solve using elimination. 4. 2x + 3y = 12 2x – y = 4 5. 5x – 2y = - 19 2x + 3y = 0
ANTONII [103]
I am attaching a document showing the steps.

3 0
3 years ago
Sean wrote a number on a piece of paper.
just olya [345]
The Sean's number is x. Formulate the equation:

x * 5 : 2 = 30
5x = 30 * 2
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Answer: the Sean's number is 12.
8 0
3 years ago
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kari74 [83]

Answer:

1st and 3rd and 5th

Step-by-step explanation:

5 0
3 years ago
Please help me check my work and correct me if I'm wrong.
Aleonysh [2.5K]
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How to solve an expression with variables in the exponents?
gtnhenbr [62]

Answer:

  use logarithms

Step-by-step explanation:

Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.

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You will note that this approach works well enough for ...

  a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents

  (x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs

but doesn't do anything to help you solve ...

  x +3 = b^(x -6)

There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.

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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.

In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.

8 0
2 years ago
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