How many hundred of purple crayons in 148305

The population of at a town has grown 2% each year. In 1998, the population of the town was about 10,000 people. What was the po

Nuetrik [128]

Answer:

10200

Step-by-step explanation:

This is an example of a compound interest. The equation for this problem is 10000*(1+2/100)^n. The n is the year as 1999 is 1 year away from 1998, you just replace n with 1 and you have a simple equation.

7 0

2 years ago

determine the dimensions of a quadrilateral with a perimeter of 48 feet that will create the smallest area

Vsevolod [243]

A quadrilateral 24 ft long and 0 ft wide will have the smallest area.

4 0

2 years ago

Patricia can drive 36 kilometers for every 3 liters of gas she puts in her car.

zloy xaker [14]

36 km
--------- = 12 km/liter
3 lit

Pat can drive 12 km per liter of gas.

5 0

3 years ago

Read 2 more answers

.A variety of stores offer loyalty programs. Participating shoppers swipe a bar-coded tag at the register when checking out and

Leni [432]

Answer:

a) Null hypothesis: $\mu \leq 120$

Alternative hypothesis: $\mu > 120$

b) $t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236$

The degrees of freedom are given by:

$df = n-1 = 80-1=79$

The p value for this case taking in count the alternative hypothesis would be:

$p_v =P(t_{79}>2.236)=0.0141$

Step-by-step explanation:

Information given

$\bar X=130$ represent the sample mean for the amount spent each shopper

$s=40$ represent the sample standard deviation

$n=80$ sample size

$\mu_o =120$ represent the value to verify

t would represent the statistic

$p_v$ represent the p value f

Part a

We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:

Null hypothesis: $\mu \leq 120$

Alternative hypothesis: $\mu > 120$

The statistic for this case would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236$

The degrees of freedom are given by:

$df = n-1 = 80-1=79$

The p value for this case taking in count the alternative hypothesis would be:

$p_v =P(t_{79}>2.236)=0.0141$

5 0

2 years ago

Match each question to the correct problem.

Maslowich

<h2>Answer:</h2>

<em>(Check attached images).</em>

<h2>Step-by-step explanation:</h2>

<h3>Exercise 1.</h3>

a. Convert to decimals.

To order the numbers from least to greaters, convert them to decimals and compare.

$5.2(percent)=0.052\\ \\\frac{1}{7} =0.1429\\\\ -0.8=-0.8000\\ \\\frac{-11}{5} =-2.2$

b. Select the second least number.

-0.8.

<h3>Exercise 2.</h3>

a. Convert to decimals.

$-3.4(percent)=-0.034\\ \\-0.031\\\\ -0.2\\ \\-\sqrt{0.8}= -0.8944$

b. Select the correct number.

$-\frac{1}{5}$ .

<h3>Exercise 3.</h3>

a. Convert to decimals.

<em>After seeing that there are negative and positive numbers, and with the premise that negative numbers are </em><u><em>always</em></u><em> lesser than positive numbers, we'll only compare the positive numbers.</em>

<em />

b. Select the correct number.

3/5.

<h3>Exercise 4.</h3>

a. Convert to decimals.

-0.35

-3.5%= -0.035

b. Conclude.

Seeing that -3.5% is less than -0.35, the symbol that makes the statement true is ">".

<h3>Exercise 5.</h3>

a. Try to visually estimate b.

B appears to have a value of -0.9.

b. Convert the numbers to decimals.

-3.4%= -0.034

-0.031

-1/5= -0.2

$-\sqrt{0.8}= -0.8944$

c. Select the correct answer.

<em>Since we estimated the value of b as -0.9, the number that best adequates to its value is </em> $-\sqrt{0.8}$ .

<h3>Exercise 6.</h3>

a. Convert to decimals.

<em>After seeing that there are negative and positive numbers, and with the premise that negative numbers are </em><u><em>always</em></u><em> lesser than positive numbers, we'll only compare the positive numbers.</em>

5.2%= 0.052

1/7= 0.1429

b. Select the correct number.

5.2% is the second largest.

<h3>Exercise 7.</h3>

a. Convert to decimals.

6/7= 0.857143

0.857

b. Select the correct answer.

Seeing that 0.857 is marked as an approximate by the

ellipsis, and considering that 6/7 is an irrational numbers, we can conclude that the number that better fits the situation and makes the statement true is "=".

<h3>Exercise 8.</h3>

a. Convert to decimals.

<em>After seeing that there are negative and positive numbers, and with the premise that negative numbers are </em><u><em>always</em></u><em> lesser than positive numbers, we'll only compare the negative numbers.</em>

<em /> $-\sqrt{21} =-4.5826$

b. Select the correct answer.

The smallest number is -4.6.

7 0

11 months ago