Answer:
2.0 seconds
Step-by-step explanation:
<u>Given quadratic functions</u>:
To find the time, in seconds, that the balloons collided at the highest point, <u>substitute</u> one equation into the other equation and rearrange to <u>equal zero</u>:
<u>Factor</u> the quadratic:
Apply the <u>zero-product property</u> to solve for x:
Therefore, the balloons collided at 1 second and 2 seconds.
To find at which time the highest point of collision occured, substitute both values of x into one of the functions:
Therefore, the time, in seconds, that the balloons collided at the highest point is 2.0 seconds.
Learn more about quadratic systems of equations here:
brainly.com/question/27930827
Part 1) <span>Given the two points (-24,7) and (30,25) a. What is an equation passing through the points?
step 1
find the slope m
m=(y2-y1)/(x2-x1)----></span>m=(25-7)/(30+24)----> m=18/54----> m=1/3
step 2
wit m=1/3 and the point (30,25)
find the equation of the line
y-y1=m*(x-x1)-----> y-25=(1/3)*(x-30)--->y=(1/3)*x-10+25
y=(1/3)*x+15
the answer Part 1) isy=(1/3)*x+15Part 2) <span>Is (51, 33) also on the same line?
</span>if the point (51.33) is on the line
y=(1/3)*x+15then
for x=51 the value of y must be 33
for x=51
y=(1/3)*51+15----> y=17+15----> y=32
32 is not 33
so
<span>the point does not belong to the given line
</span>
the answer Part 2) isthe point does not belong to the given line
see the attached figure
Simplify the following:4^5/4^4
Combine powers. 4^5/4^4 = 4^(5 - 4):4^(5 - 4)
5 - 4 = 1:Answer: 4
