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xxTIMURxx [149]
2 years ago
7

Which inequality explains why these three segments cannot be used to construct a triangle? ef fd > de ed ef < df ed ef &gt

; df ef fd < de
Mathematics
1 answer:
solniwko [45]2 years ago
3 0

We have the segments EF, FD, and DE.

Therefore, the correct answer is

ED + EF < DF

EF + FD < DE

<h3>What is Triangle Inequality Theorem?</h3>

The Triangle Inequality Theorem states that the totality of any side of a triangle must be greater than the measure of the third side in this problem.

We have the segments EF, FD, and DE.

To construct a triangle three inequalities must be met

case 1: EF + FD > DE

case 2: FD + DE > EF

case 3: EF + DE > FD

Therefore, the correct answer is

ED + EF < DF

EF + FD < DE

To learn more about inequality refer to:

brainly.com/question/17448505

#SPJ4

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Please I need help ASAP<br>pls explain your answer ​
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Answer:

47.62 cm

Step-by-step explanation:

ABCD is a rhombus. Each side measures 15 cm.

m<A = 60°.

Here are some properties of a rhombus:

Opposite angles of a rhombus are congruent.

m<C = m<A = 60°

m<ADC = m<ABC

The sum of the measures of the interior angles of a quadrilateral is 360°.

The diagonals are perpendicular bisectors of each other.

m<A + m<C + m<ADC + m<ABC = 360°

60° + 60° + 2m<ADC = 360°

2m<ADC = 240°

m<ADC = 120°

Each diagonal of a rhombus bisects a pair of congruent, opposite angles.

m<ADB + m<CDB = m<ADC

m<ADB = m<CDB

m<ADB + m<ADB = 120°

m<ADB = 60°

Triangle ABD had two angles, <A and <ADB, that measure 60°. Therefore, the third angle, <ABD also measures 60°. That makes triangle ABD an equilateral triangle.

Draw segment AT.

T is the midpoint of BD. The segment AT is the perpendicular bisector of segment BD. Triangle ATD is a 30-60-90 triangle.

Using the ratio of the lengths of the sides of a 30-60-90 triangle, we can calculate the length of AT which is the radius of circle A.

TD : AT : AD

1    : √3 :   2

AD = 15 cm

TD = AD/2

AT = √3 × TD

AT = (AD√3)/2

AT = 7.5√3 = 12.99

AQ = 12.99

perimeter = QD + PB + m(arc)PTQ + BC + CD

perimeter = (15 - 12.99) + (15 - 12.99) + 60°/360° × 2π(12.99) + 15 + 15

perimeter = 47.62

Answer: perimeter = 47.62 cm

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