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xxTIMURxx [149]
2 years ago
7

Which inequality explains why these three segments cannot be used to construct a triangle? ef fd > de ed ef < df ed ef &gt

; df ef fd < de
Mathematics
1 answer:
solniwko [45]2 years ago
3 0

We have the segments EF, FD, and DE.

Therefore, the correct answer is

ED + EF < DF

EF + FD < DE

<h3>What is Triangle Inequality Theorem?</h3>

The Triangle Inequality Theorem states that the totality of any side of a triangle must be greater than the measure of the third side in this problem.

We have the segments EF, FD, and DE.

To construct a triangle three inequalities must be met

case 1: EF + FD > DE

case 2: FD + DE > EF

case 3: EF + DE > FD

Therefore, the correct answer is

ED + EF < DF

EF + FD < DE

To learn more about inequality refer to:

brainly.com/question/17448505

#SPJ4

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9,3,1, what is the sequence and what is it equal to?
Thepotemich [5.8K]

Answer: the sequence is to divide by 3 and it gets smaller and smaller by dividing by three I don't think there is an end to it.

Step-by-step explanation:

9/3=3

3/3=1

1/3=1/3

1/3/3=1/9

1/9/3=1/27

1/27/3=1/81

and I think you know what I mean by now right?

3 0
2 years ago
Type the correct answer for each.
xxTIMURxx [149]
If point \left(x,\ \frac{\sqrt{7}}{3}\right) is on the unit ircle, then:

x^2+\left( \frac{ \sqrt{7} }{3} \right)^2=1 \\  \\ \Rightarrow x^2+ \frac{7}{9} =1 \\  \\ \Rightarrow x^2=1- \frac{7}{9} = \frac{2}{9}  \\  \\ \Rightarrow x= \sqrt{ \frac{2}{9} } = \frac{ \sqrt{2} }{3}

Since, the point is in the second quadrant, x is negative.

Thus, (x,\ y)=\left(x,\ \frac{\sqrt{7}}{3}\right)=\left(-\frac{ \sqrt{2} }{3},\ \frac{\sqrt{7}}{3}\right)

Part A:

3 \sqrt{7} =6\left( \frac{ \sqrt{7} }{2} \right) \\  \\ =6\left( \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} } \right) \\  \\ =6\left( \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } \right)=-6\left( \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } \right) \\  \\ =-6\left( \frac{y}{x} \right)=-6\tan\theta

Therefore, -6\tan\theta=3\sqrt{7}.



Part B:

- \frac{ \sqrt{7} }{2} =- \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} }  \\ \\ =- \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } = \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } = \frac{y}{x}  \\  \\ =\tan\theta

Therefore, \tan\theta=- \frac{ \sqrt{7} }{2}
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3 years ago
One rabbit saw 6 elephants while going towards River.
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1 rabbit
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castortr0y [4]
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3 0
3 years ago
This problem really confuses me, help?
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So k in the first problem would =1/2
and i guess in the second problem just put k in place of the first space and in the second space put 8 for x. y would then =4. Idk if I did this right, though, I'm honestly a little confused too.
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3 years ago
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