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xxTIMURxx [149]
2 years ago
7

Which inequality explains why these three segments cannot be used to construct a triangle? ef fd > de ed ef < df ed ef &gt

; df ef fd < de
Mathematics
1 answer:
solniwko [45]2 years ago
3 0

We have the segments EF, FD, and DE.

Therefore, the correct answer is

ED + EF < DF

EF + FD < DE

<h3>What is Triangle Inequality Theorem?</h3>

The Triangle Inequality Theorem states that the totality of any side of a triangle must be greater than the measure of the third side in this problem.

We have the segments EF, FD, and DE.

To construct a triangle three inequalities must be met

case 1: EF + FD > DE

case 2: FD + DE > EF

case 3: EF + DE > FD

Therefore, the correct answer is

ED + EF < DF

EF + FD < DE

To learn more about inequality refer to:

brainly.com/question/17448505

#SPJ4

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Step-by-step explanation:

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6 0
3 years ago
Two terms in a geometric sequence are a3=729 and a4=243.
lesantik [10]
<h2>The first term of the given sequence (a) = 6561</h2>

Step-by-step explanation:

Let the first term = a and common difference = d

Given,

a_{3} = 729 and a_{4} = 243

To find, the first term of the given sequence (a) = ?

We know that,

The nth term of a G.P.

a_{n} =ar^{n-1}

The 3rd term of a G.P.

a_{3} =ar^{3-1}

⇒ ar^{2} = 729          ..............(1)

The 4th term of a G.P.

a_{4} =ar^{4-1}

⇒ ar^{3} = 243          ..............(2)

Dividing equation (2) by (1), we get

\dfrac{ar^{3}}{ar^{2}} = \dfrac{243}{729}

⇒ r=\dfrac{1}{3}

Put r=\dfrac{1}{3} in equation (1), we get

a(\dfrac{1}{3})^{2} = 729    

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∴ The first term of the given sequence (a) = 6561

8 0
3 years ago
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