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____ [38]
3 years ago
14

Two ice cream shops in the mall sell sundaes. Let x equal the number of scoops of ice cream. Larry's ice cream shops price is re

presented by the expression 1.2x + 1. Ice cream worlds price is represented by the expression 0.4(0.3x + 1). Which statement is true?
Mathematics
1 answer:
Gnesinka [82]3 years ago
6 0

Answer:

The answer is: The two shops never charge the same price for sundaes with the same number of scoops.

Step-by-step explanation:

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Plutonium–238 has a yearly decay constant of 7.9 × 10-3. If an original sample has a mass of 15 grams, how long will it take to
eduard
The answer is 28 years

At = A0 * e^(-k * t)
At = 12 g
A0 = 15 g
k = 7.9 × 10^-3 = 0.0079 
t = ?

12 = 15 * e^(-0.0079 * t)
12/15 = e^(-0.0079 * t)
0.8 = e^(-0.0079 * t)

Logarithm both sides (because ln(e) = 1:
ln(0.8) = ln(e^(-0.0079 * t))
ln(0.8) = (-0.0079 * t) * ln(e)
-0.223 = -0.0079 * t
t = -0.223 / -0.0079
t = 28.23
t ≈ 28 years
8 0
3 years ago
What is 35 divided by 45
RSB [31]
0.77 is the answer to your question
3 0
2 years ago
Read 2 more answers
a container built in the shape of a cylinder has a circular base with a radius of 1.5 meters. the altitude of the container is 3
HACTEHA [7]

Answer:

im assuming you need the volume of this container:

Volume=\pi r^{2} h

Volume=\pi (1.5^{2} )(3.5)=24.7

8 0
3 years ago
Read 2 more answers
Hey! A step by step explanation on this would be great! Thanks!<br> (25 Points)
kicyunya [14]

Step-by-step explanation:

We find the stationary point of (20 + 2x)(1200 - 60x),

where x is the unit rate of increase/decrease.

d/dx [(20 + 2x)(1200 - 60x)]

= d/dx (-120x² + 1200x + 24000)

= -240x + 1200.

When d/dx [(20 + 2x)(1200 - 60x)] = 0,

We have -240x + 1200 = 0. => x = 5.

Price per shirt that maximise revenue

= $20 + $2x = $20 + $2(5) = $30.

Maximum revenue

= (20 + 2(5))(1200 - 60(5))

= $30 * 900 = $27,000.

6 0
2 years ago
ms. Rao buys a computer, a printer, and a scanner for $2543. the computer cost $1502 more than the printer. the printer costs $1
Mazyrski [523]
This question involves a system of equations.

for the variables we will use c for computer, p for printer, and s for scanner.

in order to solve a system of equations, we need to solve one variable, so we will just pick c because we are solving for the computer.

when we set up the
equation, we need to convert all the variables into an applicable form of c, since that is the variable we are solving for. we can do this because we have information on how the other variables differ on c.

so we get these translations:

c = c
p = c - 1502
s = p - 123

however, the scanner is not translated to c yet, it is translated into p, but we know p can translate into c, so we plug in the equation for p as so:

s = (c - 1502) - 123

which translates to

s = c - 1625

now we have

c = c
p = c - 1502
s = c - 1625

now that we have the translations, we have to use the original equation given to us which is

c + p + s = 2543

which, with our translations can be said as

c + (c - 1502) + (c - 1625) = 2543

which simplifies to

3c - 3127 = 2543.

now, we add 3127 to both sides to get

3c = 5670

then, we divide 3 to both sides to get

c = 1890

so the computer costs 1890.

if you want to find the price for the printer and scanner, simply take c and plug it in to the other equations as so.

p = 1890 - 1502 (388)
s = 1890 - 1625 (265)

6 0
3 years ago
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