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andreyandreev [35.5K]
3 years ago
14

Factor completely 4x^3 + 8x^2 − 25x − 50.

Mathematics
2 answers:
n200080 [17]3 years ago
8 0
<span>First factor like terms
4x³ + 8x² - 25x - 50
4x²(x + 2) - 25(x + 2)

See that the factor in parenthesis is the same? Because they are the same, you can pair the outside factors together in a parenthesis. 

(4x² - 25)(x+2)

factor (4x² - 25) = (2x + 5)(2x - 5)

= (2x - 5)(2x + 5)(x + 2)
</span>
matrenka [14]3 years ago
3 0
Hello there!

\boxed{ (((4 * (x^3)) +  23x^2) -  25x) -  50} \\ \\ \boxed{ ((2^2x^3 +  23x^2) -  25x) -  50} \\ \\ 4x3+8x2-25x-50   \ (is \ not \ a \ perfect \ cube.) \\ \\ We \ then \ factor \ \boxed{\boxed{ (2x + 5)  *  (2x - 5) }} \\ \\ (FINAL \ RESULT) \\ \\   \left[\begin{array}{ccc}\boxed{(2x - 5)(2x + 5)(x + 2)}\end{array}\right]

Your correct answer would be (option c).

I hope this helps you!
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P and q are complex numbers such that |p|=7√2 and |p+q|=12√3 .
gayaneshka [121]

Answer:

Option B is correct

Step-by-step explanation:

Given: \left | p \right |=7\sqrt{2}\,,\,\left | p+q \right |=12\sqrt{3}

To find: interval on which \left | q \right | must fall

Solution:

\left | p \right |=7\sqrt{2}\\-7\sqrt{2}\leq p\leq 7\sqrt{2}\,\,(i)

\left | p+q \right |=12\sqrt{3}\\-12\sqrt{3}\leq p+q\leq 12\sqrt{3}\,\,(ii)

Subtract (ii) from (i)

-12\sqrt{3}+7\sqrt{2}\leq p+q-p\leq 12\sqrt{3}-7\sqrt{2}\\-12\sqrt{3}+7\sqrt{2}\leq q\leq 12\sqrt{3}-7\sqrt{2}\\\left | q \right |=12\sqrt{3}-7\sqrt{2}

So, \left | q \right | must fall in interval [12\sqrt{3}-7\sqrt{2},\infty)

Therefore, option B is correct.

8 0
3 years ago
Colton has 8 comedy movies, 6 action movies, 5 fantasy movies, and 1 drama movie on his list of favorite movies.
Tema [17]
For every 5 movies on his list, there are 2 comedy movies.
5 0
3 years ago
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HELP ME PLZZZZZZZZZZZZ
Llana [10]

Answer:

157.5 square feet

Step-by-step explanation:

If an inch is 3 feet, then

3.5 inches = 10.5 feet (3.5*3)

5 inches = 15 feet (5*3)

The area of a rectangle is length times width so...

10.5*15 = 157.5

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Find the 9th term geometric sequence 1,1/2,1/2^2
valentinak56 [21]

Answer:   t_9=\dfrac{1}{2^8}

<u>Step-by-step explanation:</u>

t_n=t_1\times r^{n-1}\\\\Given: t_1=1,\quad r=\dfrac{1}{2}\\\\\\t_9=1\times\bigg(\dfrac{1}{2}\bigg)^{9-1}\\\\\\.\quad =\large\boxed{\dfrac{1}{2^8}}

3 0
3 years ago
Determine whether the solution of -2x = -15 is<br> Greater than or less than -15
brilliants [131]

Positive numbers are always greater than -15. Therefore, it's a greater than.

-2x = - 15

Dividing both sides by -2, we get

x = 7.5

Negative cancels on both sides, so we get a positive equation.

Positive numbers are always greater than -15. Therefore, it's a greater than.

What is greater than or less than?

  • Greater than and less than are the comparison symbols.
  • When the number is bigger or smaller than the other, then greater than and less than symbols are used.
  • If the number is greater than the other, the greater than (>) symbol is used.
  • If the number is lesser than the other, the less than the (<) symbol is used.

To learn more about greater than and less than, visit: brainly.com/question/15746367

#SPJ9

5 0
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