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andreyandreev [35.5K]
3 years ago
14

Factor completely 4x^3 + 8x^2 − 25x − 50.

Mathematics
2 answers:
n200080 [17]3 years ago
8 0
<span>First factor like terms
4x³ + 8x² - 25x - 50
4x²(x + 2) - 25(x + 2)

See that the factor in parenthesis is the same? Because they are the same, you can pair the outside factors together in a parenthesis. 

(4x² - 25)(x+2)

factor (4x² - 25) = (2x + 5)(2x - 5)

= (2x - 5)(2x + 5)(x + 2)
</span>
matrenka [14]3 years ago
3 0
Hello there!

\boxed{ (((4 * (x^3)) +  23x^2) -  25x) -  50} \\ \\ \boxed{ ((2^2x^3 +  23x^2) -  25x) -  50} \\ \\ 4x3+8x2-25x-50   \ (is \ not \ a \ perfect \ cube.) \\ \\ We \ then \ factor \ \boxed{\boxed{ (2x + 5)  *  (2x - 5) }} \\ \\ (FINAL \ RESULT) \\ \\   \left[\begin{array}{ccc}\boxed{(2x - 5)(2x + 5)(x + 2)}\end{array}\right]

Your correct answer would be (option c).

I hope this helps you!
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