The given data is
t, h: 0 2 4 6 8 10
r(t), L/h: 8.6 7.9 6.8 6.4 5.7 5.3
The lower and upper estimates for the total amount that leaked may be computed as the Left and Right Riemann sums.
The shape of the graph of r versus will determine which of the two sums yields an upper or lower sum.
The plot of the graph is shown below.
The Left Riemann sum is
Sl = 2*(8.6+7.9+6.8+6.4+5.7) = 70.8 L
The Right Riemann sum is
Sr = 2*(7.9+6.8+6.4+5.7+5.3) = 64.2 L
Answer:
The lower estimate for oil leakage is 64.2 L
The upper estimate for oil leakage is 70.8 L
By applying the Pythagorean Theorem and the Trigonometry ratio, CAH, the value of cos(M) = 4/5
<em><u>Recall:</u></em>
Trigonometry ratios, <em>SOH CAH TOA</em> can be applied to solve a right triangle.
- Pythagorean Theorem can also be applied which is: c² = b² + a², where c is the longest side (hypotenuse length).
<em><u>Given:</u></em>
ΔMNL is a right triangle
ML = 25
NL = 15
Find MN using the Pythagorean Theorem:
MN = √(ML² - NL²)
MN = √(25² - 15²)
MN = 20
To find the value of cos(M), apply the trigonometry ratio, CAH, which is:
cos ∅ = Adj/Hyp
∅ = M (reference angle)
Hypotenuse = ML = 25
Adjacent = MN = 20
cos(M) = 20/25
cos(M) = 4/5
Learn more about Trigonometry ratios on:
brainly.com/question/10417664
Answer:

Step-by-step explanation:
To find the value of y, you can create an equation where two parts of the line are equal to the whole line:

Substitute given values:

Solve for y. Simplify parentheses:

Combine like terms to simplify the equation:

Get the variable on one side of the equation and the constants on the other. Add 9 to both sides:

Subtract 9y from both sides:

Isolate the variable. Divide both sides by 10:

The value of y is 2. Insert this value into each line segment value and solve:



:Done
You can check by using:

This statement is true, so the values are correct.
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>