<span>2(3)× = 3×+1 is equal when f(x) = g(x).
f(x) is equal to g(x) when x = 0.
Therefore, the solution to the equation </span><span>2(3)×=3×+1 is x = 0.</span>
So the first thing you do is dove the equations. Let's do the numerator equation. 8(2)-4 is simply saying 8•2-4 and i don't know if u learned this in class yet but you do multiplication and division before addition and subtraction so 8•2=16-4=12 so now 12 is our numerator. Now for the denominator, 8/4=2 so 2 is our denominator. We have 12/2 but it can be simplified to 6 because 6 goes into 12 twice and u cans check this by doing 6•2=12
Hope this helps m8 :))
Step-by-step explanation: To solve this absolute value inequality,
our goal is to get the absolute value by itself on one side of the inequality.
So start by adding 2 to both sides and we have 4|x + 5| ≤ 12.
Now divide both sides by 3 and we have |x + 5| ≤ 3.
Now the the absolute value is isolated, we can split this up.
The first inequality will look exactly like the one
we have right now except for the absolute value.
For the second one, we flip the sign and change the 3 to a negative.
So we have x + 5 ≤ 3 or x + 5 ≥ -3.
Solving each inequality from here, we have x ≤ -2 or x ≥ -8.
Answer:
Step-by-step explanation:
The common difference (d) can be found using the first and 4th terms:
a1 = 3
a4 = a1 +d(4 -1)
-9 = 3 +3d . . . . . simplify
-3 = 1 + d . . . . . . divide by 3
-4 = d . . . . . . . . . subtract 1
Then ...
x = a1 + d = 3 -4 = -1
y = x + d = -1 -4 = -5
The values of x and y are -1 and -5, respectively.
